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3 years ago

5

Match each root with its meaning. (5 points) 1. Grad/gress 2. Ject 3. Meter 4. Junct 5. Loc a. Place b. To throw c. Measure d. T

o step e. To join

1 answer:

Dima020 [189]3 years ago

4 0

1. To step
2. To throw
3. Measure
4. To join
5. Place

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Using the following standard reduction potentials, Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Ni2+(aq) + 2 e- → Ni(s) E° = -0.23 V ca

lina2011 [118]

<u>Answer:</u> The above reaction is non-spontaneous.

<u>Explanation:</u>

For the given chemical reaction:

$Ni^{2+}(aq.)+2Fe^{2+}(aq.)\rightarrow 2Fe^{3+}(aq.)+Ni(s)$

Here, nickel is getting reduced because it is gaining electrons and iron is getting oxidized because it is loosing electrons.

We know that:

$E^o_{(Fe^{3+}/Fe^{2+})}=0.77V\\E^o_{(Ni^{2+}/Ni)}=-0.23V$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=-0.23-0.77=-1.0V$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

As, the standard electrode potential of the cell is coming out to be negative for the above cell. Thus, the standard Gibbs free energy change of the reaction will become positive making the reaction non-spontaneous.

Hence, the above reaction is non-spontaneous.

3 0

3 years ago

25 L of a gas is collected at 115 kPa. If the pressure increases to 300 kPa, what is the new volume?

Lina20 [59]

Answer:

V2 = 9.58 Litres.

Explanation:

Given the following data;

Initial volume = 25 L

Initial pressure = 115 kPa

Final pressure = 300 kPa

To find the new volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

$PV = K$

$P_{1}V_{1} = P_{2}V_{2}$

Substituting into the equation, we have;

$115 * 25 = 300*V_{2}$

$2875 = 300*V_{2}$

$V_{2} = \frac {2875}{300}$

$V_{2} = 9.58$

V2 = 9.58 L

Therefore, the new volume is 9.58 litres.

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3 years ago

In the experiment, 40 mL of 3 M sodium hydroxide is used to extract the benzoic acid. In order to recover the benzoic acid from

nikdorinn [45]

Answer:

20 mL OF 6 M HYDROCHLORIC ACID WILL BE NEEDED

Explanation:

M1 V1 = M2 V2

M1 = Molarity of sodium hydroxide = 3 M

V1 = volume of sodium hydroxide = 40 mL

M2 = Molarity of hydrochloric acid = 6 M

V2 = Volume of hydrochloric acid = unknown

Rearranging the equation, we have:

V2 = M1 V1 / M2

V2 = 3 * 40 mL / 6

V2 = 120 / 6

V2 = 20 mL

To precipitate the benzoic acid by 6 M of hydrochloric acid, 20 mL volume will be needed.

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A feeling of weightlessness in orbit is called

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Microgravity is your answer

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What two parts are needed to make a neutral atom of neon

almond37 [142]

Answer:

it needs two electrons in the first and eight to fill the second.

Explanation:

Because neon has two atomic shells, it needs two electrons in the first and eight to fill the second. Neon has a total of ten electrons which means two filled shells.

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