The problem above can be solved using M1V1=M2V2 where M1 is the concentration of the concentrated, V1 is the volume of the concentrated solution, M2 is the concentration of the Dilute Solution, V2 is the Volume of the dilute solution. Hence,
(3.0 M)(V2)=(250 mL)(1.2M)
V2 (3.0)= 300
V2= 100 mL
Therefore, you need 100 mL of 3.0 M HCl to form a 250 mL of 1.2 M HCl.
For sediments to become a sedimentary rock, it usually undergoes burial, compaction, and cementation. (Hope that helps)
Explanation:
After the electron configuration, the last shell of the beryllium atom has two electrons. In this case, both the valence and valence electrons of beryllium are 2. We know the details about this. The elements that have 1, 2, or 3 electrons in the last shell donate the electrons in the last shell during bond formation.
We have to calculate formula mass of N₂O.
The answer is: 44
Relative formula mass is the sum of relative atomic mass of constituent atoms in a formula unit of any compound. Relative formula mass is represented as same symbol of relative molecular mass.
To calculate relative formula mass we need to know number of each atom in the formula and then adding atomic masses of all the atoms.
In N₂O, number of N-atom present is equal to 2 and number of O-atom is equal to 1.
Atomic mass of N-atom is 14 and atomic mass of O-atom is 16.
So, formula mass of N₂O is (2 X 14)+16 = 44.
<span>According to the question-
1 mol C3H8O = 60.096 g C3H8O
2 mol C3H8O = 9 mol O2
1 mol O2 = 31.998 g O2
[(3.00 g C3H8O)/1][(1 mol C3H8O)/(60.096)][(9 mol O2)/(2 mol C3H8O)][(32.998 g O2)/(1 mol O2)] = 7.1880435 g O2
Since 7.1880435 g of O2 is needed, and 7.38 g of O2 is available, 0.199565 g of O2 will be left over and oxygen is present in excess.
Next, we need to convert 0.199565 g of O2 into moles of O2:
[(0.199565 g O2)/1][(1 mol O2)/(31.998 g O2)] = 0.005999 mol O2, or 0.006 mol O2</span>
