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zvonat [6]
3 years ago
6

In the SI units, what makes the base units special

Chemistry
1 answer:
djverab [1.8K]3 years ago
6 0

Answer:

All other units are gotten from them

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4 years ago
Nvermind i messed u. thats not what i meant to outtb ycgdgc8ydsaox agdydac bc7w
jasenka [17]

Answer:

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Explanation:

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3 years ago
Use the reaction and bond information to answer the question. H2 CO2 → CH2O2 Reactant bond energies: H–H is 432 kJ/mol, C=O is 7
Anna11 [10]

The energy absorbed by the system before the reaction start has been 752 kJ/mol.

The bond energy has been defined as the energy possessed by the bond that has been converted into the heat energy and utilized in the reaction.

The energy has been conserved in a chemical reaction. Thus, the energy absorbed by the reactant in the reaction has been the difference in the energy of the reactant and product.

<h3>Computation for the energy absorbed</h3><h3 />

The given reaction has been:

\rm H_2\;+\;CO_2\;\rightarrow\;CH_2O_2

The bond energy of the reactant has been:

H-H bond energy = 432 kJ/mol

2 C=O bond energy= 799 kJ/mol

The total energy of the reactant has been 432 kJ/mol + 799 kJ/mol

The total energy of the reactant has been 1231 kJ/mol

The bond energy of the product has been:

C-O bonds = 358 kJ/mol

C=O bonds = 745 kJ/mol

1 C-H bond = 413 kJ/mol

1 O-H bond = 467 kJ/mol

The total energy of the product has been 358 + 745 + 413 + 467 kJ/mol

The total energy of the product has been 1,983 kJ/mol

According to the law of conservation of energy:

\text{Product energy=Reactant energy + energy absorbed}

Substituting the values for energy absorbed:

\text{1,983 kJ/mol=1231\;kJ/mol+ energy absorbed}\\\rm Energy\;absorbed=1983-1231\;kJ/mol\\Energy\;absorbed=752\;kJ/mol

The energy absorbed by the system before the reaction start has been 752 kJ/mol.

Learn more about bond energy, here:

brainly.com/question/866298

7 0
2 years ago
Ne mutlu TÜRKÜM DİYENE...
Nata [24]

what is the question?


7 0
3 years ago
Read 2 more answers
A cylinder contains nitrogen and oxygen under 4.015 atm pressure. The partial pressure of N2 is 2.907 atm. What is the partial p
Aleksandr-060686 [28]

Answer: The partial pressure of the water vapor is 1.108 atm

Explanation:

According to Dalton's law, the total pressure of a mixture of gases is the sum of individual pressures exerted by the constituent gases.

p_{total}=p_A+p_B

Thus p_{total}=p_{N_2}+p_{H_2O}

Given: p_{total} =4.015 atm

p_{N_2}= 2.907 atm

p_{H_2O} = ?

Thus 4.015=2.907+p_{H_2O}

p_{H_2O}=1.108atm

Thus the partial pressure of the water vapor is 1.108 atm

8 0
3 years ago
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