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3 years ago

What kind of bonds involve a transfer of electrons? what kind of bond involves sharing of electrons?

Chemistry

2 answers:

asambeis [7]3 years ago

7 0

Answer:

While covalent bonding involves sharing electrons between two atoms, ionic bonding involves the complete transfer of electrons from one atom to another, creating positive and negative ions. These ions are then held together by the attraction between their opposite charges.

Explanation:

Hope this helped!

Ray Of Light [21]3 years ago

3 0

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.

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water from a town is suspected to contain chloride ions but not sulphate ions . describe how the presence of the chloride ions i

andreyandreev [35.5K]

Answer:

See Explanation

Explanation:

The presence of chloride ions in water can be established by adding dilute trioxonitrate V acid to a sample of the water in drops followed by aqueous silver trioxonitrate V.

If a white precipitate is formed, which is soluble in excess aqueous ammonia solution, then the presence of chloride ion in the water sample is ultimately confirmed.

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3 years ago

What is the density of chlorine gas (MM = 71.0glmol) at 1.50 atm and 25.0C

IrinaVladis [17]

Answer: D=4.35g/L

Explanation:

The formula for density is $D=\frac{M}{V}$ . M is mass in grams and V is volume in liters.

Since we are give pressure and temperature, we can use the ideal gas law to find moles/volume. FInding moles/volume would give us the base for density. All we would have to do is convert moles to grams.

Ideal Gas Law: PV=nRT

$\frac{n}{V} =\frac{P}{RT}$

$\frac{n}{V}=\frac{1.50 atm}{(0.08206Latm/Kmol)(25+274.15K)}$

$\frac{n}{V} =\frac{0.061309mol}{L}$

Now that we have moles, we can use molar mass of chlorine gas to find grams.

$0.061309mol*\frac{71.0g}{mol} =4.3529g$

With our grams, we can find our density.

$D=\frac{4.3529g}{L}$

We need correct significant figures so our density is:

$D=\frac{4.35g}{L}$

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3 years ago

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3 years ago

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alina1380 [7]

Answer:

Explanation:

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