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Alexxandr [17]
3 years ago
12

write a CER (Claim evidenc and reasoning) essay. There are problably 3-4 complete sets (ie 3-4 claims follwed by supporting evid

ence/examples and 3-4 sets of reasoning. probably will be at least one page in length if you consiser all of the CER's in this article.

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
7 0
answer: ان عدة الشهور عند الله اثنا عشر شهرا في كتاب الله يوم خلق السماوات والارض منها اربعة حرم ذلك answer: ان عدة الشهور عند الله اثنا عشر شهرا في كتاب الله يوم خلق السماوات والارض منها اربعة حرم ذلك الدين القيم فلاتظلموا فيهن انفسكم وقاتلوا المشركين كافة كما يقاتلونكم كافة واعلموا ان الله مع المتقين

explanation: ان عدة الشهور عند الله اثنا عشر شهرا في كتاب الله يوم خلق السماوات والارض منها اربعة حرم ذلك الدين القيم فلاتظلموا فيهن انفسكم وقاتلوا المشركين كافة كما يقاتلونكم كافة واعلموا ان الله مع المتقين

‎ان عدة الشهور عند الله اثنا عشر شهرا في كتاب الله يوم خلق السماوات والارض منها اربعة حرم ذلك الدين القيم فلاتظلموا فيهن انفسكم وقاتلوا المشركين كافة كما يقاتلونكم كافة واعلموا ان الله مع المتقين
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This is the question i need help on
mash [69]
I thank that your answer is C.
8 0
3 years ago
What unit is mass generally measured in
Veronika [31]

Answer:

kilograms

Explanation:

hope this helps, pls mark brainliest :D

6 0
3 years ago
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When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.
sp2606 [1]

Answer:

Mass of CaCl₂ =  20 g

CaCO is presewnt in excess.

Mass of of CaCO₃ remain unreacted =  7.007 g

Explanation:

Given data:

Mass of calcium carbonate = 25 g

Mass of hydrochloric acid = 13.0 g

Mass of calcium chloride produced = ?

Chemical equation:

CaCO₃ + 2HCl  →  CaCl₂  + H₂O + CO₂

Number of moles of CaCO₃:

Number of moles of CaCO₃ = Mass /molar mass

Number of moles of CaCO₃= 25.0 g / 100.1 g/mol

Number of moles of CaCO₃ = 0.25 mol

Number of moles of HCl:

Number of moles of  HCl = Mass /molar mass

Number of moles of HCl = 13.0 g / 36.5 g/mol

Number of moles of HCl = 0.36 mol

Now we will compare the moles of CaCl₂ with HCl and CaCO₃ .

                  CaCO₃         :               CaCl₂

                    1                 :               1

                 0.25              :            0.25

                HCl                :                CaCl₂

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

The number of moles of CaCl₂ produced by HCl are less it will be limiting reactant.

Mass of CaCl₂ = moles × molar mass

Mass of CaCl₂ =0.18 mol × 110.98 g/mol

Mass of CaCl₂ =  20 g

The calcium carbonate is present in excess.

                HCl                :                CaCO₃

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

So, 0.18 moles react with 0.36 moles of HCl.

The moles of CaCO₃ remain unreacted = 0.25 -0.18

The moles of CaCO₃ remain unreacted = 0.07 mol

Mass of of CaCO₃ remain unreacted = Moles × molar mass

Mass of of CaCO₃ remain unreacted = 0.07 mol × 100.1 g/mol

Mass of of CaCO₃ remain unreacted =  7.007 g

7 0
3 years ago
PLEASE HELP
Varvara68 [4.7K]
Ok measure atoms the answer is B
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3 years ago
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Complete the paragraph below. Do it using your Science journal or notebook
svetlana [45]

Answer:

SUSPENSION IS A KIND OF MIXTURE where particlea are visible to the naked eyes AS IT settled AT THE BOTTOM WHEN LEFT UNDISTURBED.

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