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Paul [167]
4 years ago
6

How many Br atoms are in 1.98 g of Br?

Chemistry
1 answer:
Mkey [24]4 years ago
7 0

Answer:

1.5 x 10²²atoms

Explanation:

Given parameters:

Mass of Br = 1.98g

Unknown:

Number of atoms

Solution:

A mole of a substance is the amount of substance contained in the avogadro's number of particles.

To solve this problem, we must first find the number of moles present in the given mass of the Br atom:

       Number of moles = \frac{mass}{molar mass} =  \frac{1.98}{80}  = 0.025mole.

Now we know that:

       1 mole = 6.02 x 10²³

      0.025 mole = 0.025 x 6.02 x 10²³ = 1.5 x 10²²atoms

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A mass of 2.20 kg of sodium phosphate is converted number of moles
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A sample was prepared by mixing 18. ml of 3.00 x 10^-3 m crystal violet (cv) with 2.00 ml of 0.250 m naoh. calculate the resulti
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Answer : The resulting concentrations of CV and NaOH are 0.0027 M and 0.025 M respectively.

Explanation :

Step 1 : Find moles of crystal violet and NaOH.

The molarity formula is

Molarity = \frac{mol}{L}

Molarity of crystal violet = 3.00 \times 10^{-3} = \frac{mol (CrystalViolet)}{L}

The volume of crystal violet solution is 18 mL which is 0.018 L.

Moles of crystal violet = 3.00 \times 10^{-3} \times 0.018 = 5.4 \times 10^{-5}

Moles of crystal violet = 5.4 x 10⁻⁵

Moles of NaOH = Molarity \times L = 0.250 \times 0.00200 = 5.00 \times 10^{-4}

Moles of NaOH = 5.00 x 10⁻⁴

Step 2 : Find total volume of the solution

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Step 3 : Use molarity formula to find final concentrations

Molarity of crystal violet = \frac{mol(CrystalViolet)}{Total Volume(L) } = \frac{5.4 \times 10^{-5}}{0.020} = 2.7 \times 10^{-3}

Final concentration of CV = 0.0027 M

Molarity of NaOH= \frac{mol(NaOH)}{Total Volume(L) } = \frac{5.00 \times 10^{-4}}{0.020} = 0.025 \times 10^{-3}

NaOH is a strong base and dissociates completely as follows.

NaOH (aq) \rightarrow Na^{+} (aq) + OH^{-} (aq)

The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.

Concentration of OH⁻ = 0.025 M

8 0
3 years ago
What’s the two products of H2Co3
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Answer:

Hydrogen and Cobalt

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