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2 years ago

12

I need help as fast as possible

1 answer:

musickatia [10]2 years ago

4 0

Na is 57.48%, O is 40% and H is 2.52%

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water absorbs and releases large amounts of heat before its temperature changes because water has a high

barxatty [35]

Waters high heat capacity is a property focused by hydrogen bonding among water molecules.When heat is absorbed,hydrogen bonds are broken and water molecules can move freely.When the temperature of water decreases, the hydrogen bonds are formed and release a considerable amount of energy

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3 years ago

What is an example of an organ A.pancreas B.blood C.insulin D.knee

marissa [1.9K]

Answer: pancreas

Explanation:

4 0

3 years ago

Read 2 more answers

Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac

valentinak56 [21]

Answer : The value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

Explanation :

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = $25^oC=273+25=298K$

Q = reaction quotient

First we have to calculate the $\Delta G_^o$ .

Formula used :

$\Delta G^o=-RT\times \ln K_p$

Now put all the given values in this formula, we get:

$\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})$

$\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole$

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$CO(g)+2H_2(g)\rightarrow CH_3OH(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}$

$Q=8.1\times 10^{5}$

Now we have to calculate the value of $\Delta G_{rxn}$ by using relation (1).

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

Now put all the given values in this formula, we get:

$\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})$

$\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole$

Therefore, the value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

3 0

3 years ago

Zinc + Hydrochloric acid — Zinc chloride + Hydrogen [Zn +2 HCI → ZnCl2 + H2] is an

Jet001 [13]

Double replacement i believe

6 0

3 years ago

4. In a solution, what pulls particles into the solution?

Tanya [424]

The correct answer to your question is B, solvent.
let me know if you have any further questions
:)

3 0

3 years ago