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ddd [48]
3 years ago
5

What is the empirical formula of the compound with the molecular formula c18h36?

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0
When we write a formula of a compound in its simplest form, it is empirical formula.
Given the molecular formula is = C₁₈H₃₆
Now we can relate both empirical and molecular formula as;
Molecular formula = n x empirical formula
C₁₈H₃₆ = 18 x CH₂
So the empirical formula of C₁₈H₃₆ is CH₂
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where P1 = initial pressure of gas = 80.0 kPa

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T1 = initial temperature of gas = 240 °C = (240 + 273) K = 513 K

P2 = final pressure of gas = 107 kPa

V2 = final volume of gas = 20.0 L

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Substituting the values,

(80.0 kPa × 10.0 L) ÷ (513 K) = (107 kPa × 20.0 L) ÷ T2

T2 = 513 K × (107 kPa ÷80.0 kPa) × (20.0 L ÷ 10.0 L)

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T2 = 1372.275 K

T2 = (1372.275 - 273) °C

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8 0
3 years ago
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