Answer:
sope syrup cooking oil milk water
Explansation:
You can establish a system of two equation with two variables.
Varibles are:
V1 = volume of the 50% sugar solution
V2 = volumen of the 80% sugar solution
Equations:
Balance of sugar:
Sugar from 50% solution: 0.5*V1
Sugar from 80% solution: 0.8*V2
Sugar in the final solution (mix): 0.6 * 105 = 63
1) 0.5V1 + 0.8V2 = 63
Final volume = volume of 50% solution + volume of 80% solution
2) V1 + V2 = 105
From (2) V1 = 105 - V2
Substitue in (1)
0.5 (105 - V2) + 0.8 V2 = 63
52.5 - 0.5V2 + 0.8V2 = 63
0.3 V2 = 63 - 52.5
0.3 V2 = 10.5
V2 = 10.5/0.3
V2 = 35mL
V1 = 105 - 35 = 70 mL
Answer: 70 mL of the 50% solution and 35 mL of the 80% solution.
Answer:
reduced
Explanation:
To win the metallic product from the oxide, it demands that the metal be reduced.
During reduction a metal will:
- gain electrons.
- there would be removal of oxygen from the specie
- there would be decrease in oxidation number of the atom
- decrease in the number of electronegative atom surrounding the element.
The specie that is reduced will become the oxidant and reducing agent in the chemical reaction.
