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Kamila [148]
3 years ago
11

How many total minutes does she read if she read for 20 minutes for the first day and everyday after that she reads five minutes

longer then the previous day for thirty days.
Mathematics
1 answer:
allsm [11]3 years ago
3 0

Answer:

so on the first day she read 20 and the next they read 25 and the next day they read 30 for those thirty days add five and hopefully you will get ur answer


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Answer this please!!!
vivado [14]

Answer:

$40

Step-by-step explanation:

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2 years ago
Evaluate the limit 9n^3 + 5n - 2/2n^3
VikaD [51]

Answer:

9/2    if  n goes to infinity  and that the 2n^3 is under the whole expression

Step-by-step explanation:

Let me clear this .

find  limit  (9n^3  + 5*n  - 2)/ (2n^3)

as n --> infinity

Did I put the parentheses in the right spot?

because if you leave it the way you did, then the whole expression goes to positive infinity as n goes to infinity  But I will do this with parentheses

so

find  limit  (9n^3  + 5*n  - 2)/ (2n^3)

simplify expression

limit   (9/2)  +   5/(2n^2)   -   1/(n^3)

=  (9/2)  + 0  - 0

=  (9/2)

4 0
3 years ago
Line segment AB has endpoints at B (2 , 4) and A (22 , 4). Find point C so that it is located 3/4 of the way from A to B.
Igoryamba

Answer:

need points

Step-by-step explanation:

need points

4 0
3 years ago
A jet flies at a rate of 1.3x10 to the 6 feet per hour. Written in scientific notation, which is the best estimate of how many f
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This is scientific notation

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Read 2 more answers
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
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