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3 years ago

Ok whoever helps me is da best so plz :) 50 points

Mathematics

1 answer:

Nikolay [14]3 years ago

8 0

Answer:

A(-2/3)

B(-1/6)

C(1/2)

D(4/3)

Step-by-step explanation:

There are 6 tics in each section.

That means each tic is 1/6

A(-4/6) -> (-2/3)

B(-1/6)

C(3/6) -> (1/2)

D(8/6) -> (4/3)

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2 years ago

If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?

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Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

20 * 20 * 20 * 20 * 20

First number 2nd number 3rd number 4th number 5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are $20^{5}$ ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

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This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are $15^{5}$

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