Question

A gas originally at 27 °C and 1.00 atm pressure in a 3.3 L flask is cooled at constant pressure until the temperature is 11 °C. The new volume of the gas is ________ L.

Answer 1

Answer:

THE NEW VOLUME OF THE GAS IS 3.124 L

Explanation:

Initial Temperature = 27°C = 27 + 273 K = 300 K

Pressure = constant

Initial Volume = 3.3 L

Final Temperature = 11 °C = 11+ 273 K = 284 K

Final volume = unknown

Using Charles' law, at constant pressure, the volume of a given gas is directly proportional to the temperature.

Mathematically,

V1 / T1 = V2 / T2

Re-arranging the formula by making V2 the subject of the formula

V2 = V1 T2 / T1

V2 = 3.3 * 284 / 300

V2 = 3.124 L

The new volume of the gas is therefore 3.124 L at 11°C