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Step2247 [10]
2 years ago
12

PLEASE HELP!!

Chemistry
2 answers:
ryzh [129]2 years ago
7 0

Answer:

0.16

Explanation:

patriot [66]2 years ago
6 0

Answer:

0.16 M

Explanation:

We are given;

  • Volume of NaOH as 34.8 mL
  • Volume of HCl as 29.6 mL
  • Molarity of HCl is 0.19 M

We are required to determine the concentration of the NaOH

We are going to write the equation of the reaction first;

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

We can then determine the number of moles HCl

Moles = Molarity × volume

          = 0.19 M × 0.0296 L

          = 0.005624 moles

We the determine the number of moles of NaOH

From the equation;

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = moles of HCl

                     = 0.005624 moles

Finally, we determine the concentration of NaOH

Concentration/Molarity = Number of moles ÷ Volume

                                      = 0.005624 moles ÷ 0.0348 L

                                      = 0.1616 M

                                      = 0.16 M

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marshall27 [118]
Using charles law
v1/t1=v2/t2
v1=49ml
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Explanation:

Hello, the numerical procedure is shown in the attached file.

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Answer:

See explanation

Explanation:

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