Answer:
0.16 M
Explanation:
We are given;
- Volume of NaOH as 34.8 mL
- Volume of HCl as 29.6 mL
- Molarity of HCl is 0.19 M
We are required to determine the concentration of the NaOH
We are going to write the equation of the reaction first;
NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)
We can then determine the number of moles HCl
Moles = Molarity × volume
= 0.19 M × 0.0296 L
= 0.005624 moles
We the determine the number of moles of NaOH
From the equation;
1 mole of NaOH reacts with 1 mole of HCl
Therefore;
Moles of NaOH = moles of HCl
= 0.005624 moles
Finally, we determine the concentration of NaOH
Concentration/Molarity = Number of moles ÷ Volume
= 0.005624 moles ÷ 0.0348 L
= 0.1616 M
= 0.16 M
