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Alla [95]
2 years ago
8

What viral components might serve as good targets for the design of antiviral chemicals?

Chemistry
1 answer:
densk [106]2 years ago
8 0
Specific events in virus replication identified as targets for antiviral agents are viral adsorption, penetration, uncoating, and viral nucleic acid synthesis as well as viral protein synthesis.

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Hey guys!
melamori03 [73]

Pajamas

Out fit for each day + 2 extra

Athletic clothes

Light hoodie

Bathing suit + cover up

Underwear

Socks

Bra's

Sunscreen

Moisturizer

Makeup

Makeup remover

Shampoo + conditioner

Shaving cream

Razor

Medicine (pain meds, etc.)

Lotion

Chapstick

Retainer (if you have 1)

Tooth brush + toothpaste

Deodorant

Monthly Items

Phone charger

Computer + computer charger

Camera + camera charger

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Snacks

Perfume

Book

Glasses

Purses

Jewelry

Watch

Wallet

Hat

Sunglasses

Hand sanitizer

Tennis shoes

Walking shoes

Flip flops

Blow dryer

Straightner

Hair clips

Hair ties

Hair brush

Hair spray

Heat protection

Have music + shows/ movies downloaded

Hope this helps you take off anything you don't want or anything you don't need

7 0
3 years ago
30 mL of 0.6 M HCl solution is neutralized with 90 mL NaOH solution. What is the concentration of the base? Show all work Please
skad [1K]

From

<em>n</em><em>a</em><em>=</em><em>1</em>

<em>n</em><em>b</em><em>=</em><em>1</em>

<em>V</em><em>a</em><em>=</em><em>3</em><em>0</em><em>m</em><em>l</em><em>s</em>

<em>V</em><em>b</em><em>=</em><em>9</em><em>0</em><em>m</em><em>l</em><em>s</em>

<em>M</em><em>a</em><em>=</em><em>0</em><em>.</em><em>6</em><em>M</em>

<em>M</em><em>b</em><em>=</em><em>?</em>

<em>f</em><em>r</em><em>o</em><em>m</em>

<em>Mb</em><em>=</em><em><u>M</u></em><em><u>a</u></em><em><u>×</u></em><em><u>V</u></em><em><u>a</u></em><em><u>×</u></em><em><u>n</u></em><em><u>b</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>V</em><em>b</em><em>×</em><em>n</em><em>a</em>

<em>M</em><em>b</em><em>=</em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>×</u></em><em><u>3</u></em><em><u>0</u></em><em><u>×</u></em><em><u>1</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>9</em><em>0</em><em>×</em><em>1</em>

<em>m</em><em>b</em><em>=</em><em><u>1</u></em><em><u>8</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>9</em><em>0</em>

<em>M</em><em>b</em><em>=</em><em>0</em><em>.</em><em>2</em><em>M</em>

<em>NaOH</em><em>=</em><em>4</em><em>0</em>

<em>F</em><em>r</em><em>o</em><em>m</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>m</em><em>o</em><em>l</em><em>a</em><em>r</em><em>i</em><em>t</em><em>y</em><em>×</em><em>m</em><em>r</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>0</em><em>.</em><em>2</em><em>×</em><em>4</em><em>0</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>8</em><em>g</em><em>/</em><em>m</em><em>o</em><em>l</em>

3 0
2 years ago
Convert 3.30 g of copper (II) hydroxide Cu(OH)2 to molecules.
ratelena [41]

Answer:

0.18× 10²³ molecules

Explanation:

Given data:

Mass of copper hydroxide = 3.30 g

Number of molecules = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 3.30 g/97.56 g/mol

Number of moles = 0.03 mol

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.03 mol × 6.022 × 10²³ molecules / 1mol

0.18× 10²³ molecules

6 0
2 years ago
What are some differences between Boiling &amp; Evaporation?
Angelina_Jolie [31]
Boiling happens much faster! Boiling also takes place at the bottom of the fluid whereas evaporation takes place at the top.


Hope this helps!

3 0
3 years ago
Read 2 more answers
Provide the organometallic reagent that is needed to perform the transformation shown below. The reagent should be formatted as
Juliette [100K]

The correct answer is   LiCH_{3}CH(CH_{3} )CH_{3} .

<h3>Organometallic reagent</h3>

Organometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.

Learn more about organometallic reagent here:

brainly.com/question/13299409

#SPJ4

4 0
2 years ago
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