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Alla [95]
2 years ago
8

What viral components might serve as good targets for the design of antiviral chemicals?

Chemistry
1 answer:
densk [106]2 years ago
8 0
Specific events in virus replication identified as targets for antiviral agents are viral adsorption, penetration, uncoating, and viral nucleic acid synthesis as well as viral protein synthesis.

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What is the molarity of a solution that contains 17 g of nh3 in 0.50 l of solution?
Sauron [17]

Answer:

  • 2.0 M

Explanation:

<u>1) Data:</u>

a) M = ?

b) mass of solue = 17 g

c) solute: NH₃

d) V = 0.5o liter

<u>2) Formulae:</u>

a) number of moles, n = mass in grams / molar mass

b) M = n / V (in liters)

<u>3) Solution</u>

a) Molar mass of NH₃ = 17.03 g/mol

b) n = mass in grams / molar mass = 17 g / 17.03 g/mol = 0.998 mol NH₃

c) M = n / V (in liters) = 0.998 mol / 0.50 liter = 1.996 M

d) Round to the appropiate number of significant figures, 2: 2.0 M.

Answer: 2.0 M

8 0
3 years ago
A reactant decomposes with a half-life of 29.5 s when its initial concentration is 0.229 M. When the initial concentration is 0.
Dmitrij [34]

Answer :

The order of reaction is, 0 (zero order reaction).

The value of rate constant is, 0.00388Ms^{-1}

Explanation :

Half life : It is defined as the time in which the concentration of a reactant is reduced to half of its original value.

The general expression of half-life for nth order is:

t_{1/2}\propto \frac{1}{[A_o]^{n-1}}

or,

\frac{t_{1/2}_1}{t_{1/2}_2}=\frac{[A_2]^{n-1}}{[A_1]^{n-1}}

or,

n=\left(\frac{\log\frac{(t_{1/2})_1}{(t_{1/2})_2}}{\log\frac{(A)_2}{(A)_1}}\right )+1           .............(1)

where,

t_{1/2} = half-life of the reaction

n = order of reaction

[A] = concentration

As we are given:

Initial concentration of A = 0.229 M

Final concentration of A = 0.639 M

Initial half-life of the reaction = 29.5 s

Final half-life of the reaction = 82.3 s

Now put all the given values in the above formula 1, we get:

n=\left (\frac{\log \frac{29.5}{82.3}}{\log\frac{0.639}{0.229}}\right )+1

n=0.000196\approx 0

Thus, the order of reaction is, 0 (zero order reaction).

Now we have to determine the rate constant.

To calculate the rate constant for zero order the expression will be:

t_{1/2}=\frac{[A_o]}{2k}

When,

t_{1/2} = 29.5 s

[A_o] = 0.229 M

29.5s=\frac{0.229M}{2k}

k=0.00388Ms^{-1}

Thus, the value of rate constant is, 0.00388Ms^{-1}

4 0
3 years ago
Need help with this now please! Lots of points!
liubo4ka [24]
Here are the energy profile diagrams, p.s. sorry couldn’t find any plain paper!
8 0
3 years ago
Which of the following is an example of element? A.Water B.Chlorine C.Carbon Dioxide D.Sugar
prisoha [69]
The answer is B chlorine. Chlorine is and elements and the others are compounds.
8 0
3 years ago
At what temperature does water freeze?
Wewaii [24]

Answer:

32 degrees

Explanation:

8 0
3 years ago
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