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jonny [76]
4 years ago
8

Classify these compounds as acid, base, salt, or other.? 1. ch3oh 3. hno3 5. nabr

Chemistry
2 answers:
Nesterboy [21]4 years ago
7 0

Explanation:

Acids are the species which upon dissociation in water gives hydrogen ions (H^{+}).

For example, HNO_{3} is acidic in nature because upon dissociation it releases H^{+} ions as follows.

            HNO_{3} \rightarrow H^{+} + NO^{-}_{3}

Whereas bases are the species which upon dissociation in water gives hydroxide ions (OH^{-}).

For example, NaOH is basic in nature as it releases OH^{-} ions.

Salts are the substances formed by combination of two or more different oppositely charged ions.

For example, NaCl is a salt.

Therefore, we classify the given compounds as acid, base, salt, or other as follows.

  • CH_{3}OH - Other
  • HNO_{3} - Acid
  • NaBr - Salt

ELEN [110]4 years ago
5 0
<span> </span><span>1. Alcohol(other) 
3. Acid 
5. Salt 

</span>
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Indicate which solution in each pair has the lower pH. Your response should be a four letter "word". The first letter should be
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Answer:

bcfh

Explanation:

HClO₄ reacts with water thus:

HClO₄ + H₂O → H₃O⁺ + ClO₄⁻

That means HClO₄ produce H₃O⁺ that decreases pH. That means the higher concentration of HClO₄ decreases pH. Thus, lower pH will be:

b) 0.2 M HClO4

The reaction of NaClO₄ is:

NaClO₄ + H₂O → OH⁻ + HClO₄ + Na⁺

The higher concentration of NaClO₄ the higher production of OH⁻ that increase pH, that means the lower concentration of NaClO₄ the lower pH, thus, the answer is:

<em>c) 0.1 M NaClO or</em>

HF reacts with water thus;

HF ⇄ H⁺ + F⁻

The equilibrium constant is:

k = [H⁺] [F⁻] / [HF] = 3,5x10⁻⁴

For HNO₂ equilibrium is:

HNO₂ ⇄ H⁺ + NO₂⁻

k = [H⁺] [NO₂⁻] / [HNO₂] = 4,5x10⁻⁴

As k value is higher for HNO₂, the concentration of H⁺ will be higher in this system doing the HNO₂ with the lower pH.

f) 0.1 M HNO2

NaOH is a strong base that produce OH⁻ that increase pH, pure water is neutral, thus, the lowe pH is:

h) pure water

I hope it helps!

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