A solution of sodium nitrate will get make litmus paper wet. A solution of NaNO3 is neutral. Therefore, there is no change in color.
The amount of Na₂SO₄ would be 15.09 grams
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
4NaOH + 2H₂SO₄ --> 2Na₂SO₄ + 4H₂O
Mole ratio of NaOH and Na₂SO₄ = 2:1
Mole of 8.50 grams of NaOH = 8.50/40
= 0.21 mole
Equivalent mole of Na₂SO₄ = 0.21/2
= 0.11 mole
Mass of 0.11 mole Na₂SO₄ = 0.11 x 142.04
= 15.09 grams
More on stoichiometric reactions can be found here: brainly.com/question/8062886
Well, a molecule of this carbohydrate would essentially have no electronegativity difference as it is a Nonpolar compound, and not that of a polar one. All electrons between the atoms would ultimately have a net dipole value of 0, indicating that the molecule is Nonpolar. Thus does not have a partial positive and or a partial negative charge.
molar concentration of AgNO₃ solution = 0.118 mole/L
Explanation:
Because we have the volume of the solution and there is no information about the density of the solution I will asume that you ask for the molar concentration.
number of moles = mass / molecular weight
number of moles of AgNO₃ = 10 / 170 = 0.0588
molar concentration = number of moles / volume (L)
molar concentration of AgNO₃ solution = 0.0588 / 0.5
molar concentration of AgNO₃ solution = 0.118 mole/L
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molar concentration
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Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:
