Question

The value of ?G�\' for the conversion of 3-phosphoglycerate to 2-phosphoglycerate (2PG) is 4.4 kJ/mol. If the concentration of 3-phosphoglycerate at equilibrium is 2.35 mM, what is the concentration of 2-phosphoglycerate? Assume a temperature of 25.0 �C. The constant R = 8.3145 J/(mol�K)

Answer 1

Answer:

0.3983 mM is the concentration of 2-phosphoglycerate.

Explanation:

3-phosphoglycerate ⇄  2-phosphoglycerate , ΔG° = 4.4 kJ/mol

Concentration of  3-phosphoglycerate at equilibrium = 2.35 mM

Concentration of  2-phosphoglycerate at equilibrium = x

Equilibrium constant of the reaction at 25°C = $K_c=\frac{x}{2.35 mM}$

$\Delta G^o=-RT\ln K_{c}$

$4400 J/mol=-8.3145 J/mol K\times 298.15 K\times \ln [\frac{x}{2.35 mM}]$

$\ln [\frac{x}{2.35 mM}]=\frac{4400 J/mol}{-8.3145 J/mol K\times 298.15 K}$

$\ln [\frac{x}{2.35 mM}]=-1.7750$

$\frac{x}{2.35 mM}=0.1695$

x = 0.3983 mM

0.3983 mM is the concentration of 2-phosphoglycerate.