Question

A bus starting from rest moves with a uniform acceleration of 0.1 ms ^-2 for 2 minutes.Find the speed acquired then find the distance travelled

Answer 1

1) Speed acquired
The time taken for the motion is
$t=2 min=2 \cdot 60 = 120 s$
The bus is moving by uniformly accelerated motion, with constant acceleration $a=0.1 m/s^2$, so the speed acquired by the bus after 120 s is
$v(t) = at=(0.1 m/s^2)(120 s)=12 m/s$

2) The distance traveled is given by the following formula:
$S= \frac{1}{2}at^2$
where a is the acceleration and t the time. Substituting numbers into the equation, we find
$S= \frac{1}{2}(0.1 m/s^2)(120 s)^2=720 m$