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castortr0y [4]
3 years ago
15

The use of drugs to treat disease is called?

Physics
2 answers:
Thepotemich [5.8K]3 years ago
8 0
Medication -----------
Mila [183]3 years ago
5 0
The use of drugs to treat disease is called medication
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Which statement best explains acceleration? A. It is the total distance covered over a period of time. B. It is a change in velo
tatuchka [14]

I think the answer is C.

8 0
3 years ago
Read 2 more answers
the fabric of the hot air balloon can stretch, but it does not allow air to pass through it. think about the change in air densi
Karolina [17]
It would definitely stretch and wouldn't do anything as long as there is no holes in it.
3 0
4 years ago
Two forces one of 12N and another of 5N act on abody in such away that they makes an angel of 90 with each other, what is the re
Murljashka [212]

Answer:

13 N

Explanation:

From the question,

If two forces act at right angle to each other, Their result force can be calculated using Pythagoras theorem.

R'² = R₁²+R₂²....................... Equation 1

Where R' = Resultant force, R₁ = First force, R₂ = Second force.

Given: R₁ = 12 N, R₂ = 5 N

Substitute these values into equation 1

R'² = 12²+5²

R'² = 144+25

R'² = 169

R' = \sqrt{169}

R' = 13 N.

Hence the resultant force is 13 N

6 0
3 years ago
A calculator displays a result such as 1,365 248 0 107 kg. The estimated uncertainty in the result is 2%. How many digits should
Lera25 [3.4K]

Answer:

4) three

Explanation:

Assuming you mean 1.365248×10⁷, 2% of that is:

0.02 (1.365248×10⁷) = 0.027305×10⁷

So the number is:

1.365248×10⁷ ± 0.027305×10⁷

We need to round this number so that there is uncertainty only in the last digit.

1.37×10⁷ ± 0.03×10⁷

There are three significant figures in 1.37.

8 0
3 years ago
An aluminum cylinder with a radius of 2.7 cm and a height of 67 cm is used as one leg of a workbench. The workbench pushes down
soldier1979 [14.2K]

Answer:

1.9\times 10^{-4}

1.2\times 10^{-4}\ m

Explanation:

r = Radius = 2.7 cm

F = Force = 3.2\times 10^4\ N

A = Area = \pi r^2

\sigma = Stress = \frac{F}{A}

E = Young's modulus = 7\times 10^{10}\ Pa

\epsilon = Strain

L_0 = Original length = 67 cm

\Delta L = Change in length

Young's modulus is given by

E=\frac{\sigma}{\epsilon}\\\Rightarrow \epsilon=\frac{\sigma}{E}\\\Rightarrow \epsilon=\frac{\frac{3.2\times 10^4}{\pi 0.027^2}}{7\times 10^{10}}\\\Rightarrow \epsilon=0.0001996=1.9\times 10^{-4}

Strain is 1.9\times 10^{-4}

Strain is given by

\epsilon=\frac{\Delta L}{L_0}\\\Rightarrow \Delta L=\epsilon\times L_0\\\Rightarrow \Delta L=1.9\times 10^{-4}\times 0.67\\\Rightarrow \Delta L=0.0001273\\\Rightarrow \Delta L=1.2\times 10^{-4}\ m

The cylinder height decreases by 1.2\times 10^{-4}\ m

3 0
3 years ago
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