Also need help with 20 & 21 please

Marat540 [252]

Answer:

The generator will work only if the magnetic field associated with the turns of coil change.

here both magnet and coil are stationary with respect to each other so no electromagnetic induction would take place. so no indiced current will be produced.

the student has to introduce some mechanism either to rotate the coil or the magnet

5 0

4 years ago

Which compound has the highest boiling point? Explain your reasoning. CH4 or CH3CH3

kogti [31]

The bigger molecule has more interactions and hence the higher b.p. CH3CH2OCH2CH3 is a bigger molecule than CH4 and CH3CH3, so has more dispersion forces. It also has dipole-dipole forces due to the polarised C-O bonds. CH3OH and CH3CH2OH have hydrogen bonds due to the very electronegative O atom bonded to the H atom

God bless

4 0

3 years ago

Read 2 more answers

The MAC is 58 inches, The CG limits are from 26% to 43% MAC. If the CG is found to be

eimsori [14]

By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.

<h3>What are the limits?</h3>

First, we need to find the limits.

We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.

So if 58 in is the 100%, the 26% and 43% of that are:

26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.

But we know that the CG is found to be 45.5% MAC, then it measures:

(45.5%/100%)*58in = 0.455*58in = 26.39 in

We need to compare it with the largest limit, so we get:

26.39 in - 24.94 in = 1.45 in

This means that the CG is 1.45 inches out of limits.

If you want to learn more about percentages, you can read:

brainly.com/question/14345924

6 0

2 years ago

Suppose one night the radius of the earth doubled but its mass stayed the same. What would be an approximate new value for the f

Alex17521 [72]

Answer:

g' = g/4

Explanation:

The value of the free-fall acceleration at the surface of the earth, can be obtained applying Newton's 2nd law, assuming that the only force acting on an object at the surface of the earth, is the one produced by the mass of the Earth, i.e. gravity.
This force can be expressed according the Newton's Universal Law of Gravitation , as follows:

$F_{g} = G*\frac{m_{x} *m_{E} }{r_{E}^{2} } (1)$

From Newton's 2nd Law, we have:
$F = m* a (2)$
Since the left sides in (1) and (2) are equal each other, both right sides must be equal each other also.
Simplifying the mass m, we can write the acceleration a in (2) as the acceleration due to gravity, g, as follows:

$g = G*\frac{m_{E} }{r_{E}^{2} } (3)$

Since G is an universal constant, and the mass mE remains constant, if we double the radius of the Earth, the new value for the acceleration due to gravity (let's call it g'), is as follows:

$g' = G*\frac{m_{E} }{(2r_{E})^{2} } =G*\frac{m_{E} }{4*r_{E}^{2} } = g*\frac{1}{4} =\frac{g}{4} (4)$

4 0

3 years ago

Which copper wire would have the highest resistance?

Dafna11 [192]

Answer:

Just consider the resistance as water flowing through a pipe. If the pipe is too small in radius (consider thin wire as small pipe) water can’t flow easly. If the pipe is big in radius (consider thick wire as big pipe) water can flow easly. So flowing water through a small pipe for a long distance will inversly affect the normal flow where as flowing water through a big pipe for a small distance will not affect too much the normal flow.

So long & thin wire has high resistance. Short & thick wire has low resistance.

B. A wire that is 2 m long and has a cross-sectional area of 0.066

7 0

3 years ago