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Eva8 [605]
2 years ago
13

Also need help with 20 & 21 please

Physics
2 answers:
SSSSS [86.1K]2 years ago
5 0
Number 20 is B and 21 is C
Hoochie [10]2 years ago
5 0
A density is a physical change
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the answer is sueist

Explanation:

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Which disease do you think is most easily spread? 5 Answers
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coronavirus

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3 years ago
A beam of light strikes a sheet of glass at an angle of 56.6° with the normal in air. You observe that red light makes an angle
Yuri [45]

Answer:

(a). Index of refraction are n_{red} = 1.344 & n_{violet} = 1.406

(b). The velocity of red light in the glass v_{red} = 2.23 ×10^{8} \ \frac{m}{s}

The velocity of violet light in the glass v_{violet} =2.13 ×10^{8} \ \frac{m}{s}

Explanation:

We know that

Law of reflection is

n_1 \sin\theta_{1} = n_2 \sin\theta_{2}

Here

\theta_1 = angle of incidence

\theta_2 = angle of refraction

(a). For red light

1 × \sin 56.6 = n_{red} × \sin 38.4

n_{red} = 1.344

For violet light

1 × \sin 56.6 = n_{violet} × \sin 36.4

n_{violet} = 1.406

(b). Index of refraction is given by

n = \frac{c}{v}

n_{red} = 1.344

v_{red} = \frac{c}{n_{red} }

v_{red} = \frac{3(10^{8} )}{1.344}

v_{red} = 2.23 ×10^{8} \ \frac{m}{s}

This is the velocity of red light in the glass.

The velocity of violet light in the glass is given by

v_{violet} = \frac{3(10^{8} )}{1.406}

v_{violet} =2.13 ×10^{8} \ \frac{m}{s}

This is the velocity of violet light in the glass.

8 0
3 years ago
3 cases where kinetic energy become potential energy
finlep [7]
--  Toss a rock straight up.  The kinetic energy you give it
with your hand becomes potential energy as it rises. 
Eventually, when its kinetic energy is completely changed
to potential energy, it stops rising.

--  When you're riding your bike and going really fast, you come
to the bottom of a hill.  You stop pedaling, and coast up the hill.
As your kinetic energy changes to potential energy, you coast
slower and slower.  Eventually, your energy is all potential, and
you stop coasting.

--  A little kid on a swing at the park.  The swing is going really fast
at the bottom of the arc, and then it starts rising.  As it rises, the
kinetic energy changes into potential energy, more and more as it
swings higher and higher.  Eventually it reaches a point where its
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8 0
3 years ago
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How much work must be done to bring three electrons from a great distance apart to 5.0×10^−10 m from one another (at the corners
Inessa05 [86]

Answer:

1.38 x 10^-18 J

Explanation:

q = - 1.6 x 10^-19 C

d = 5 x 10^-10 m

the potential energy of the system gives the value of work done

The formula for the potential energy is given by

U =\frac{Kq_{1}q_{2}}{d}

So, the total potential energy of teh system is

U =\frac{Kq_{1}q_{2}}{d}+\frac{Kq_{2}q_{3}}{d}+\frac{Kq_{1}q_{3}}{d}

As all the charges are same and the distance between the two charges is same so the total potential energy becomes

U =3\times \frac{Kq^{2}}{d}

K = 9 x 10^9 Nm^2/C^2

By substituting the values

U =3\times \frac{9\times 10^{9}\times \ 1.6 \times 1.6 \times 10^{-38}}{5\times 10^{-10}}

U = 1.38 x 10^-18 J

6 0
3 years ago
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