<h2>
Option 3, 216 m is the correct answer.</h2>
Explanation:
We have initial velocity, u = 15 m/s
Time, t = 12 seconds
Final velocity, v = 21 m/s
We have equation of motion v = u + at
Substituting
21 = 15 + a x 12
a = 0.5 m/s²
Now we have equation of motion v² = u² + 2as
21² = 15² + 2 x 0.5 x s
s = 216 m
Displacement = 216 m
Option 3, 216 m is the correct answer.
Answer:
1287.5 N
Explanation:
We are given that
Mass of vehicle ,m=2100 kg
Weight of vehicle ,F=20,600 N
Area,A=
We have to find the minimum force that must be applied to the attached piston of area in order to lift the vehicle.
Apply the pascal's law
Answer:
5.11 kg
Explanation:
Hooke's law states that stress is directly proportional to strain. It can be represented by the equation:
F = -kx
Where x is the displacement of the spring’s end from its equilibrium position, F is the force applied to the spring, k is a constant known as spring constant.
At first a force (F) of 62 N i used to stretch a spring by 12 cm (x).
Substituting into Hooke's equation:
F = kx
k = F/x = 62 / 12 = 5.17 N/cm
The spring is then held vertically and an object. The object is acted by upon by acceleration due to gravity since it is vertically upward. Therefore the force created by the object F = mg where g = acceleration due to gravity = 9.8 m/s². It causes a stretch (x) of 9.7 cm
Therefore:
mg = 5.17 N/cm × 9.7 cm
9.81m = 50.117
m = 50.117 / 9.81 = 5.11 kg
The work-energy theorem states that the change in kinetic energy of the particle is equal to the work done on the particle:
The work done on the particle is the integral of the force on dx:
So, this corresponds to the change in kinetic energy of the particle.