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3 years ago

The force required to make an object travel along a circular path is:

Physics

2 answers:

AVprozaik [17]3 years ago

6 0

it the centripetal force

trust me

garik1379 [7]3 years ago

6 0

Answer:

centripetal force

Explanation:

just did this on a question

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A bicyclist travels at the speed of 25 kilometers per hour for 5 hours. How far does the bicyclist go?

mixas84 [53]

Answer:

125 kilometers

Explanation:

Speed= 25km/h

Time = 5 h

Distance= Speed x Time

= 25 x 5

= 125 km

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3 years ago

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Ac soucre change it polarity how many time

Karolina [17]

Alternating current (AC) flows half the time in one direction and half the time in the other, changing its polarity 120 times per second with 60-hertz current.

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3 years ago

Help with 3 please! I will give brainliest!

rusak2 [61]

The answer is point b because vertical velocity is zero at the maximum height

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3 years ago

. An unbalanced force of 500 N is applied to a 75 kg object. What is the acceleration of the object?

Hoochie [10]

The acceleration of the object is $6.7 m/s^2$

Explanation:

We can solve the problem by using Newton's second law, which states that the net force exerted on an object is equal to the product between the mass of the object and its acceleration:

$F=ma$

where

F is the net force

m is the mass of the object

a is its acceleration

For the object in this problem,

F = 500 N is the applied force

m = 75 kg is the force

Solving the equation for a, we find the acceleration:

$a=\frac{F}{m}=\frac{500}{75}=6.7 m/s^2$

Learn more about Newton's second law:

brainly.com/question/3820012

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5 0

3 years ago

An emf of 28.0 mV is induced in a 501 turn coil when the current is changing at a rate of 12.0 A/s. What is the magnetic flux th

dmitriy555 [2]

Answer:

Φ = 5.589×10⁻⁵ Wb

Explanation:

The inductance of a coil is given as

L = e/(di/dt) ..................... Equation 1

Where L = inductance of the coil, e = induced e.m.f, di/dt = rate of change of current in the coil.

Also,

The inductance of each turn of the coil when a magnetic field is step up in the coil is

L = NΦ/i ................. Equation 2

Where N = number of turns, Φ = magnetic field, i = current.

equating equation 1 and equation 2

e/(di/dt) = NΦ/i

making Φ the subject of the equation,

Φ = (e×i)/N.(di/dt) .................. Equation 3

Given: e = 28.0 mV = 0.028 V, N = 501 turns, di/dt = 12.0 A/s, i = 4.00 a

Substitute into equation 3,

Φ = (0.028×4)/(12×501)

Φ = 0.112/2004

Φ = 5.589×10⁻⁵ Weber

Φ = 5.589×10⁻⁵ Wb

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3 years ago