Question

A body is dropped from a height of 30m. What is the velocity of the body after it has covered a distance of 20 m? (Given g= 10 m/s 2)
please fast

Answer 1

Answer:

approximately 19.8  m/s

If using g = 10 m/s^2, the answer rounds to 20 m/s

Explanation:

You can use the kinematic formula that relates distance covered, velocities and acceleration (without time dependence) given by:

$v_f^2-v_i^2=2\,*\,a\,*displacement$

which in our case becomes:

$v_f^2-0=2\,*\,(9.8\,\frac{m}{s^2}) \,*(20\,m)\\v_f^2=392\\v_f\approx 19.8\,\frac{m}{s}$

If using g = 10 m/s^2, the answer is 20 m/s

Answer 2

Answer:

the velocity is 20m/s

Explanation:

data given

1. Height (h)=20m
2. Gravity (g)=10m/s2
3. velocity v = 0
4. velocity u =?

$v2 = u2 - 2gh$

0 = u2 - 2 (10)(20)

0 = u2 - 400

400 = u2

20m/s = u