3 years ago

How do very small objects behave?

Physics

2 answers:

nataly862011 [7]3 years ago

7 0

A. very small objects behave like like particles.

In-s [12.5K]3 years ago

7 0

Answer:

A) PARTICLES

Explanation:

VERY SMALL OBJECTS ARE BEHAVE LIKE A PARTICLES.

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The freezer compartment in a conventional refrigerator can be modeled as a rectangular cavity 0.3 m high and 0.25 m wide with a

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Answer:

Thickness of Styrofoam insulation is 0.02741 m.

Explanation:

Given that,

Height = 0.25 m

Depth = 0.5 m

Power = 400 W

Temperature = 33°C

We need to calculate the area of Styrofoam

Using formula of area

$A=2(lb+bh+hl)$

Put the value into the formula

$A=2(0.3\times0.5+0.25\times0.5+0.5\times0.3)$

$A=0.85\ m^2$

Inner surface temperature of freezer

$T_{i}=-10°C=263\ K$

Outer surface temperature of freezer

$T_{o}=33+273=306\ K$

We need to calculate the thickness of Styrofoam insulation

Using Fourier law,

$q=\dfrac{kA}{L}(T_{o}-T_{i})$

$L=\dfrac{kA}{q}(T_{o}-T_{i})$

Put the value into the formula

$L=\dfrac{0.30\times0.85}{400}(306-263)$

$L=0.02741\ m$

Hence, Thickness of Styrofoam insulation is 0.02741 m.

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2 years ago

When an object radiates heat, the strength of this radiation far from the object decreases when distance from the source increas

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B I am not sure about the answer but it may be B

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In which part of the scientific method do you tell why the research is being done?

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You tell it in pupouse

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3 years ago

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Single Replacement: HCI + Zn

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During a single replacement, the Zn and H will switch places. That means the product formed will be ZnCl and H2.

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A point P1 is located by the vector A = (3.74)î + (1.64)ĵ and a point P2 is located by the vector B = (1.60)î + (3.66)ĵ. The vec

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Answer:

$\vec{C} = ( \ - 2.14 \ , \ 2.02 \ )$

Explanation:

The vector that point from point P1 to point P2 its found simply by taking the vector at which point P2 its located and subtracting the vector at which point P1 its located:

$\vec{C} = \vec{B} - \vec{A}$

So:

$\vec{C} = ( \ 1.60 \ , \ 3.66 \ ) - ( \ 3.74 \ , \ 1.64 \ )$

$\vec{C} = ( \ 1.60 \ - \ 3.74 \ , \ 3.66 \ - \ 1.64 \ )$

$\vec{C} = ( \ - 2.14 \ , \ 2.02 \ )$

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3 years ago