Answer:
Answer: C Scrum
Explanation:
Answer: C Scrum would BEST support this objective, to collect and evaluate user stories related to the organization’s internally designed CRM tool.
The answer is C) Availability.
Although the company is addressing scalability by adding more servers, the question is asking for security requirement. Therefore we need to choose one of the principles from CIA triad which includes confidentiality, integrity, and availability.
Integrity involves keeping the data accurate and confidentiality involves keeping the data between the sender and intended recipient(s). That being said, scalability and availability are the possible answers.
C) Availability is the best answer because it is part of the CIA triad.
Note: Another resource to look at for cyber security principles would be the Parkerian Hexad.
A list is an R-object that can have a wide range of different items inside of it, including vectors, functions, and even another list.
The head() function lets you display the first observations in a data frame. The method tail() prints the final observations in your data collection in a manner similar to that. Both head() and tail() print a top line called the 'header', which contains the names of the distinct variables in your data collection. The R language's transform() function is used to alter data. The first parameter is transformed into a data frame. A suitable variable name comprises of letters, numbers and the dot or underline characters. The variable name does not begin with a number but rather with a letter or a dot.
Learn more about variable here-
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Something like a hard drive.
Answer:
Check the explanation
Explanation:
223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.
The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000
Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)
So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26
Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)
and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25
Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)
So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28
