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Archy [21]
3 years ago
13

Which organ system carries materials to human tissues?

Chemistry
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

Cardiovascular they carry according to me

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What is the ph of a solution that is 0.50 m in propanoic acid and 0.40 m in sodium propanoate. (ka for propanoic acid = 1.3 x 10
max2010maxim [7]
<span>The pH is given by the Henderson - Hasselbalch equation:
              pH = pKa + log([A-]/[HA])
              pH = -log(</span><span>1.3 x 10^-5) + log(0.50/0.40)
              pH = 4.98
The answer to this question is 4.98.
</span>
3 0
3 years ago
Does it take a lot of heat to melt a substance with a low melting point t
Helga [31]

low melting point means that a low amount of heat is required to melt said substance.

3 0
3 years ago
What is the concentration of kl solution if 20.68g of solute was added to enough water to form 100ml solution?
rewona [7]

Answer:

1.25 M

Explanation:

Step 1: Given data

Mass of KI (solute): 20.68 g

Volume of the solution: 100 mL (0.100 L)

Step 2: Calculate the moles of solute

The molar mass of KI is 166.00 g/mol.

20.68 g × 1 mol/166.00 g = 0.1246 mol

Step 3: Calculate the molar concentration of KI

Molarity is equal to the moles of solute divided by the liters of solution.

M = 0.1246 mol/0.100 L= 1.25 M

5 0
2 years ago
Wet snow is best for snow man building<br>​
fredd [130]

Answer:

<h2>Hope my answer helps</h2>

Explanation:

<h2>Moist to wet snow is the ideal moisture content needed to build the best snowman. If the snow is too dry, it is comparable to loose powder and in turn, the snow won't stick together. On the other hand, if the snow has too much moisture and is slushy, it can't form into a solid.</h2>
4 0
2 years ago
The activation energy of a certain uncatalyzed reaction is 64 kJ/mol. In the presence of a catalyst, the Ea is 55 kJ/mol. How ma
Ksivusya [100]

Answer:

About 5 times faster.

Explanation:

Hello,

In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

\frac{k_1}{k_2}=\frac{Aexp(-\frac{Ea_1}{RT} )}{Aexp(-\frac{Ea_2}{RT})}  \\\frac{k_1}{k_2}=\frac{exp(-\frac{Ea_1}{RT} )}{exp(-\frac{Ea_2}{RT})}

By replacing the corresponding values we obtain:

\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8

Such result means that the catalyzed reaction is about five times faster than the uncatalyzed reaction.

Best regards.

4 0
3 years ago
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