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Eduardwww [97]
3 years ago
9

How many significant figures are in the measurement 40,500 mg?

Chemistry
1 answer:
schepotkina [342]3 years ago
3 0

b) three

this is because all integers are sig figs, and all numbers between integers are sig figs. This makes the 40,5 part of 40,500 significant. Place holder zeroes that are not after a decimal are not significant, so the last two zeroes of the number are not significant.

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TiliK225 [7]

Answer:

one is across

Explanation:

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2 years ago
predicting outcomes a mixture contains cobalt metal, copper metal, and tin metal. this mixture is mixed with nickel nitrate. whi
Temka [501]

The metal that will react is Cobalt.

The equation for the reaction is,

Co + Ni(NO3)2 → Co(NO3)2 + Ni

The above reaction is an example of Displacement Reaction. Displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound.

Cobalt is more reactive than Nickle in the reactivity series so it displaces Nickle from Nickle Nitrate and forms Cobalt Nitrate.

Reactivity series is a list of metals arranged in decreasing order of their reactivity. The metals with the greatest reactivity are at the top, followed by those with the lowest reactivity. Higher-ranking metals in a series can force lower-ranking metals out of their salt solution for any two metals in the series.

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7 0
1 year ago
An unknown gas effuses 2. 165 times faster than xe. what is the molar mass of the gas? show the set up and answer with unit
enot [183]

27.94 g/mole is the molar mass of the unknown gas.

Use Graham's Law, which indicates that the square root of a gas's molar mass determines its rate of effusion.

The following equation compares two distinct gases, (a) and (b), and expresses this:

sqrt(M(b)/M) = R(a)/R(b) (a)

R is the effusion rate.

square root = sqrt

the molar mass, M

In response to your query, if gas (a) is the unknown gas and Xe(M = 131 g/mol) is the second gas, we have:

sqrt(M(Xe)/M(a) = 2.165, where R(a)/R(Xe)

Square both sides, and you get:

(2.165)² = 131 g/mol/ M (a)

M(a)(2.165)² = 131

M(a) is equal to 131/(2.165)² = 27.94 g/mol.

Having a molar mass of 27.94 g/mol, the unknown gas.

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8 0
1 year ago
What is the molecular formula of a molecule that has an empirical formula of CH and a molecular mass of 78.11 g
sveticcg [70]

Answer: C6H6

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Solution:

78.11 g CH / 13 g CH = 6

5 0
3 years ago
The graph of several pressure-volume readings on a contained gas at constant temperature would be
tigry1 [53]

Answser: a curved line.


Justification:


Boyle's law states that a constant temperature the volume of a certain amount of gas is inversely related to the pressure:<em> pV = k.</em>


The graph of two inverseley related variables is a curve: as one variable increases the other decresases.


In such a curve for any pair of points it is obeyed Boyle's law: pV = constant, so:

<em>         p₁V₁ = p₂V₂ = p₃V₃ = ... = k</em>


Mathematically, the graph represents a hyperbola: as the value of one of the variables increase the other trends to zero, so the curve approaches the axis without touching them.


See the figure attached to visualize the form of the curve.

8 0
3 years ago
Read 2 more answers
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