Question

If you produce .65moles of carbon dioxide when aluminum carbonate is decomposed, how many moles of aluminum carbonate did you start with?

Answer 1

0.22 moles of Al₂(CO₃)₃

Explanation:

The decomposition reaction of aluminium carbonate (Al₂(CO₃)₃):

Al₂(CO₃)₃ → Al₂O₃ + 3 CO₂

Taking account the chemical reaction we devise the following reasoning:

if        1 mole of Al₂(CO₃)₃ produces 3 moles of 3 CO₂

then  X moles of Al₂(CO₃)₃ produces 0.65 moles of 3 CO₂

X = (1 × 0.65) / 3 = 0.22 moles of Al₂(CO₃)₃

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decomposition reaction

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