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3 years ago

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A human lung at maximum capacity has a volume of 3.0 liters. If the partial pressure of oxygen in the air is 21.1 kilopascals an

d the air temperature is 295 K, how many moles of oxygen are in the lung?

1 answer:

MrRa [10]3 years ago

3 0

Answer : 0.026 moles of oxygen are in the lung

Explanation :

We can solve the given question using ideal gas law.

The equation is given below.

$PV = nRT$

We have been given P = 21.1 kPa

Let us convert pressure from kPa to atm unit.

The conversion factor used here is 1 atm = 101.3 kPa.

$21.1 kPa \times \frac{1atm}{101.3kPa}= 0.208 atm$

V = 3.0 L

T = 295 K

R = 0.0821 L-atm/mol K

Let us rearrange the equation to solve for n.

$n = \frac{PV}{RT}$

$n = \frac{0.208atm\times 3.0L}{0.0821 L.atm/mol K\times 295 K}$

$n = 0.026 mol$

0.026 moles of oxygen are in the lung

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