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nikdorinn [45]
3 years ago
10

Which of the following reactions would result in decreased entropy? (multiple choice)

Chemistry
1 answer:
jasenka [17]3 years ago
8 0

Answer:

D

Explanation:

Since the state of matter is going from a gas to a solid, it would be going from a state of high entropy (greater disorder) to a state of lower entropy (less disorder).

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An unknown quantity of methane gas, CHA, is held in a 2.00-liter container at 77°C. The pressure inside the container is 3.00 am
kolbaska11 [484]

Answer:

0.21\text{ mol}

Explanation:

Here, we want to calculate the number of moles of methane in the container

From the ideal gas law:

\begin{gathered} PV\text{ = nRT} \\ n\text{ = }\frac{PV}{RT} \end{gathered}

where:

P is the pressure inside the container which is 3 atm

V is the volume of the container which is 2 L

R is the molar gas constant which is 0.0821 Latm/mol.k

T is the temperature in Kelvin (we convert the temperature in Celsius by adding 273 : 273 + 77 = 350 K)

n is the number of moles that we want to calculate

Substituting the values, we have it that:

n=\text{ }\frac{3\times2}{0.0821\text{ }\times350}\text{ = 0.21 mol}

6 0
1 year ago
Give me an example of pedegriee
Nana76 [90]
The ability to roll your tongue is determined by the dominant gene.
3 0
4 years ago
9. Let's say, you need to make 2.00 L of 0.05 M copper (II) nitrate solution. How many grams of
Vlad [161]

Answer:

18.76 g of copper II nitrate

Explanation:

Now recall that we must use the formula;

n= CV

Where;

n= number of moles of copper II nitrate solid

C= concentration of copper II nitrate solution

V= volume of copper II nitrate solution

Note that;

n= m/M

Where;

m= mass of solid copper II nitrate

M= molar mass of copper II nitrate

Thus;

m/M= CV

C= 0.05 M

V= 2.00 L

M= 187.56 g/mol

m= the unknown

Substituting values;

m/ 187.56 g/mol = 0.05 M × 2.00 L

m= 0.05 M × 2.00 L × 187.56 g/mol

m= 18.76 g of copper II nitrate

Therefore, 18.76 g of copper II nitrate is required to make 0.05 M solution of copper II nitrate in 2.00 L volume.

6 0
3 years ago
To improve air quality and obtain a useful product, chemists often remove sulfur from coal and natural gas by treating the conta
Norma-Jean [14]

Answer:

1) Increase

2) Decreases

3) increases

4) Increase

Explanation:

These questions can only be answered by considering the principle which states that, "When a constraint such as a change in concentration, pressure or volume is imposed on a reaction system in equilibrium. The system will readjust itself in order to annul the constraint."  

Now, if more reactants are added, the equilibrium position will shift towards the right, If more products are added, the equilibrium position will shift to the left.

Similarly, the removal of H2S causes the O2 concentration to increase since the equilibrium position now shifts to the left.

Also, addition of O2 causes H2S to be removed as the equilibrium moves to the right.

8 0
3 years ago
Why alkali metals easly ionize
Dmitriy789 [7]
Here’s what I found:

It takes very little energy to remove that outermost electron from an alkali metal. Thus, alkali metals easily lose their outermost electron to become a +1 ion. ... In fact, as you go down the 1A column, the first ionization energies get lower and lower, making cesium the most easily ionized element on the periodic table.

So basically it’s because part of what makes alkali metals so reactive is that they have one electron in their outermost electron layer.
7 0
3 years ago
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