(0.6x^4)(0.2x^6)
<span>
=<span><span>0.6<span>x^4</span></span>*<span>0.2<span>x^6</span></span></span></span><span>
=<span><span><span>0.6*<span>x^4</span></span>*0.2</span>*<span>x^6</span></span></span><span>
=<span><span>(<span>0.6*0.2</span>)</span>*<span>(<span><span>x^4</span>*<span>x^6</span></span>)</span></span></span><span>
=<span>0.12*<span>x^10</span></span></span><span>
=<span>0.12<span>x^<span>10</span></span></span></span>
Answer:
Step-by-step explanation:
Given
Solving (a): In vertex form
The vertex form of an equation is:
To do this, we make use of completing the square method.
We have:
------------------------------------------------------------------
Take the coefficient of x (i.e. -6)
Divide by 2; -6/2 = -3
Square it: (-3)^2 = 9
Add and subtract the result to the equation
------------------------------------------------------------------
Factorize 
Factor out x - 3
Express as squares
Hence, the vertex form of is:
Solving (b): State the coordinates of the vertex.
In ; the vertex is: (h,k)
The vertex of will be
An <u>example of a problem</u> where I <em>would not</em> group the addends differently is:
3+2+4.
An <u>example of a problem</u> where I <em>would</em> group the addends differently is:
2+5+8.
Explanation:
In the <u>first problem</u>, I would not group the addends differently before adding. This is because I cannot make 5 or 10 out of any of the numbers. We group addends together to make "easier" numbers for us to add, such as 5 and 10. If we cannot do that, there is no reason to regroup the addends.
In the <u>second problem</u>, I would regroup like this:
2+8+5
This is because 2+8=10, which makes the problem "easier" for us to add. Since we can get a number like this that shortens the process, we can regroup the addends.
What is the variables replacement
