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Norma-Jean [14]

3 years ago

10

If hari buys 20biscuits for Rs 200 and sells it for Rs 100 find the loss

2 answers:

dimulka [17.4K]3 years ago

6 0

Answer:

hdvbn

Step-by-step explanation:

nfshvjjnmmnjjmbm

vlabodo [156]3 years ago

6 0

He buys 20 biscuits for 200 (1 biscuit for 10)
And sells 20 biscuits for 100 (1 biscuit for 5)
The loss is 100

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(x³-3x²+2x+1/x²-4x+4)dx(dx/Dy)+(x²+4y-y²)/(²√4y+y²) solve for dx/dy<br><br>

Furkat [3]

It’s 22/3 I think so that’s the answer

4 0

3 years ago

So confused some one help

SOVA2 [1]

Answer:

-2 (filled in circle) to 7 (open circle)

Step-by-step explanation:

for the first equation x must be the equal to or smaller than 6. so -3(-2) equals 6 but anything less than -2, let's say -3(-3), will be BIGGER than six, so -2 including -2 which is a filled in circle.

solving it:

-3(x) $\leq$ 6

$\frac{-3x}{-3} \leq \frac{6}{-3}$

$x\leq -2$

for the second equation x must be smaller than 17. so first you take out + 3 by subtracting it, leaving the equation as 2x<14. 2(7)<14 is NOT true so anything bigger than 7 leaves it as true because 6.98934747483 can still make it true, so anything smaller than 7 which is 7 with a not filled in, or open, circle

solving it:

$2x + 3 (- 3) < 17 (- 3)$

2x < 14

$\frac{2x}{2}$

x < 7

my explanation is all over the place, but hope this helps!!!

4 0

3 years ago

Three functions are given below: f(x), g(x), and h(x). Explain how to find the axis of symmetry for each function, and rank the

SpyIntel [72]

for f(x) = -2(x-4)2+2 - set equation to y = -2(x-4)2+2, solve x-4=0, x = 4

axis of symmetry is x = 4

for g(x) = 5x2-10x+7, set equation to y = 5x2-10x+7, solve the square: 5x2 becomes 5(x-1)2 solve x-1 = 0, x = 1

axis of symmetry is x=1

for H(x) what x value would be the centerline so that the graph symmetry is the same on both sides? looking at the graph the top of the arc is on -2

so axis of symmetry is x = -2

6 0

3 years ago

What is the value of 1/4 {38-14} + 3^3 divided by 9

labwork [276]

$\huge\text{Hey there!}$

$\mathsf{\dfrac{1}{4} (38 -14) + \dfrac{3^3}{9}}$

$\mathsf{38-14=\bf 24}$

$\mathsf{= \ \dfrac{1}{4} (24)+\dfrac{3^3}{9}}$

$\mathsf{\dfrac{1}{4}(24)= \bf 6}$

$\mathsf{= \ 6+\dfrac{3^3}{9}}$

$\mathsf{3^3}\\\mathsf{= 3\times3\times3}\\\mathsf{= 9\times3}\\\mathsf{= \bf 27}$

$\mathsf{= \ 6+\dfrac{27}{9}}$

$\mathsf{\dfrac{27}{9}}\\\mathsf{= 27\div9}\\\mathsf{= \bf 3}$

$\mathsf{= \ 6 + 3}$

$\mathsf{= \bf 9}$

$\boxed{\boxed{\huge\text{Therefore, your ANSWER is: \textsf 9}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

3 years ago

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Evaluate the expression when y = 4. 5 + y + 8

AlexFokin [52]

Answer: 17

Step-by-step explanation:

3 0

3 years ago

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