Answer:
The last answer choice is correct, I am pretty sure.
Just go on the calculator (like Desmos) and just use the decimals to determine which one is true.
<span>If you have a high confidence level, the chance of rejecting the null hypothesis is rare.
If you have a low confidence level, the chance of of rejecting the null hypothesis is nonexistent.
If you have a low confidence level, the chance of of rejecting the null hypothesis is rare.
If you have a high confidence level, the chance of of rejecting the null hypothesis is high.</span>
Answer:
its C
Step-by-step explanation:
Answer:
x > -3
![\sf (-3, \infty)](https://tex.z-dn.net/?f=%5Csf%20%28-3%2C%20%5Cinfty%29)
Step-by-step explanation:
Domain: input values (x-values)
Monotonic increasing: always increasing.
A function is increasing when its graph rises from left to right.
The graph of a quadratic function is a parabola. If the leading term is positive, the parabola opens upwards. The domain over which the function is increasing for a parabola that opens upwards is values greater than the x-value of the vertex.
<u>Vertex</u>
Standard form of quadratic equation: ![\sf y=ax^2+bx+c](https://tex.z-dn.net/?f=%5Csf%20y%3Dax%5E2%2Bbx%2Bc)
![\textsf{x-value of vertex}=\sf -\dfrac{b}{2a}](https://tex.z-dn.net/?f=%5Ctextsf%7Bx-value%20of%20vertex%7D%3D%5Csf%20-%5Cdfrac%7Bb%7D%7B2a%7D)
Given function:
![\sf y=x^2+6x](https://tex.z-dn.net/?f=%5Csf%20y%3Dx%5E2%2B6x)
Therefore, x-value of function's vertex:
![\sf \implies x= -\dfrac{6}{2}=-3](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20x%3D%20-%5Cdfrac%7B6%7D%7B2%7D%3D-3)
<u>Final Solution</u>
The function is increasing when x > -3
![\sf (-3, \infty)](https://tex.z-dn.net/?f=%5Csf%20%28-3%2C%20%5Cinfty%29)
Answer:
c. (x+4)(2x)•(x + 4)(3x)
Step-by-step explanation: