Answer:
The average induced emf is 50.88 V
Explanation:
Given;
number of turns, N = 80 turns
angle between the plane of the coil and magnetic field, θ = 43°
strength of magnetic field, B = 1.40 T
time to make 80 turns = 0.0700 s

where;
A is the area of the coil = 0.25 x 0.4 = 0.1 m²
If the plane makes an angle of 43° with a magnetic field to a position perpendicular to the field, then the initial angle θi = 90 - 43 = 47° and the final angle θf with the field = 0

Therefore, the average induced emf is 50.88 V