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Ivahew [28]
3 years ago
5

What is the speed of a person travelling 30 meters in 5 seconds?

Physics
2 answers:
miss Akunina [59]3 years ago
6 0

Answer:

s

Explanation:

kifflom [539]3 years ago
3 0

Answer:

6\:\mathrm{m/s}

Explanation:

Denote average speed by S=\frac{d}{t} where d is total distance travelled and t is time.

Plugging in given values, we get:

S=\frac{30}{5}=\fbox{$6\:\mathrm{m/s}$}.

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Trava [24]

Answer:

2

Explanation:

6 0
3 years ago
3. What are the challenges of looking for Dyson spheres?
S_A_V [24]

1. it is difficult to search for it . Because infrared rays will never penetrate through earth atmosphere.

2. we are unaware of how it looks like and we only know it is red and will glow . A damaged star also looks like this.

3. Dust also makes is hard to detect Dyson spheres . So we will get confused between Dyson sphere and a star surrounded by dust.

5 0
3 years ago
Read 2 more answers
A billiard ball strikes and rebounds from the cushion of a pool table perpendicularly. The mass of the ball is 0.38 kg The ball
xxTIMURxx [149]

Answer:

Force is 432.94 N along the rebound direction of ball.

Explanation:

Force is rate of change of momentum.

\texttt{Force}=\frac{\texttt{Final momentum-Initial momentum}}{\texttt{Time}}

Final momentum = 0.38 x -1.70 = -0.646 kgm/s

Initial momentum = 0.38 x 2.20 = 0.836 kgm/s

Change in momentum = -0.646 - 0.836 = -1.472 kgm/s

Time = 3.40 x 10⁻³ s

\texttt{Force}=\frac{\texttt{Final momentum-Initial momentum}}{\texttt{Time}}=\frac{-1.472}{3.40\times 10^{-3}}\\\\\texttt{Force}=-432.94N

Force is 432.94 N along the rebound direction of ball.

7 0
3 years ago
Answer this question ASAP <br><br>( this is about basketball. )
mixer [17]

Answer:

1. shoot to hard

2. too short

Explanation:

7 0
3 years ago
Read 2 more answers
9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en
masha68 [24]

Answer:

2.61 atm

Ley de Boyle

Explanation:

P_1 = Presión inicial = 0.96 atm

P_2 = Presión final

V_1 = Volumen inicial = 95 mL

V_2 = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.

4 0
2 years ago
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