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sineoko [7]
3 years ago
8

Which term defines seeking some way of achieving a goal by overcoming obstacles or finding an answer to a question?

Physics
1 answer:
irga5000 [103]3 years ago
8 0

Answer:

Problem solving

hope this helps :)

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Planetary orbits... are spaced more closely together as they get further from the Sun. are evenly spaced throughout the solar sy
BaLLatris [955]

Answer:

E) are almost circular, with low eccentricities.

Explanation:

Kepler's laws establish that:

All the planets revolve around the Sun in an elliptic orbit, with the Sun in one of the focus (Kepler's first law).

A planet describes equal areas in equal times (Kepler's second law).

The square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit (Kepler's third law).

T^{2} = a^{3}

Where T is the period of revolution and a is the semi-major axis.

Planets orbit around the Sun in an ellipse with the Sun in one of the focus. Because of that, it is not possible to the Sun to be at the center of the orbit, as the statement on option "C" says.

However, those orbits have low eccentricities (remember that an eccentricity = 0 corresponds to a circle)

In some moments of their orbit, planets will be closer to the Sun (known as perihelion). According with Kepler's second law to complete the same area in the same time, they have to speed up at their perihelion and slow down at their aphelion (point farther from the Sun in their orbit).

Therefore, option A and B can not be true.

In the celestial sphere, the path that the Sun moves in a period of a year is called ecliptic, and planets pass very closely to that path.  

4 0
3 years ago
How long does it take an airplane to fly 5000 m if it maintains a speed of 240 meters per second?
kolbaska11 [484]

Answer:

20 5/6 sec

Explanation:

To find the solution we divide 5000 by 240

However, when you see a problem, always try to simplify

5000/240=500/24=250/12=125/6

Now the division is much easier

20 5/6 sec

8 0
3 years ago
What is the uses of echoes​
Anestetic [448]

Answer:

Echoes are the reflection of sound from relatively flat object that is far enough away that you can discern the time difference. Echoes are used to measure distance, velocity, and the shape of objects. Echoes off gratings result in an unusual pinging sound

6 0
3 years ago
Calculate the potential energy stored in a metal ball of a mass of 80 kg kept at a height of 15m from the earth surface.What wil
True [87]

Answer:

39200 joules

the potential energy will be zero

Explanation:

we know that potential energy is found by multiplying mass, acceleration due to gravity and height from the Earth's surface

so it will be

potential energy= mgh

80x9.8x15

= 39200 joules

the potential energy of the mental ball will be zero when kept on the Earth's surface because the height from the Earth's surface will be zero and zero multiplied to any number is zero only

I have a doubt with the second one, this is what I think it is. Consult your teacher if you think my answer for the second one is wrong

6 0
3 years ago
Read 2 more answers
An all-electric car (not a hybrid) is designed to run from a bank of 12.0 V batteries with total energy storage of 2.30 ✕ 107 J.
AnnyKZ [126]

Answer:

a) I=733.33\ A

b) d=52272.7273\ m

c) d'=51948.0519\ m

Explanation:

Given:

  • voltage of the battery, V=12\ V
  • energy storage capacity of the battery, E=2.3\times 10^7\ J
  • speed of the car, v=20\ m.s^{-1}

a)

power drawn by the car, P=8.8\ kW

<u>Now the Current delivered to the motor:</u>

we the relation between the power and electrical current,

P=V.I

8800=12\times I

I=733.33\ A

b)

<u>Distance travelled before battery is out of juice:</u>

we first find the time before the battery runs out,

t=\frac{E}{P}

t=\frac{2.3\times 10^7}{8800}

t=2613.636\ s

Now the distance:

d=v.t

d=20\times 2613.636

d=52272.7273\ m

c)

When the head light of 55 W power is kept on while moving then the power   consumption of the car is:

P'=P+55

P'=8800+55

P'=8855\ W

<u>Now the time of operation of the car:</u>

t'=\frac{E}{P'}

t'=\frac{2.3\times 10^7}{8855}

t'=2597.4026\ s

<u>Now the distance travelled:</u>

d'=v.t'

d'=20\times 2597.4025

d'=51948.0519\ m

5 0
3 years ago
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