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igomit [66]
3 years ago
7

NEED HELP ASAP PLEASEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Which of the following is an example of work being done on an object?
A.
A man pushes a couch across the room.
B.
A prism scatters ultraviolet light into visible light.
C.
A box rests on the floor.
D.
Water in a pot changes into steam.

In the diagram above, which letter identifies an axle?
A.
X
B.
Z
C.
Y
D.
W

Which simple machine can be described as a shaft that is attached to the center of a wheel?
A.
lever
B.
inclined plane
C.
pulley
D.
wheel and axle

Usually, levers are used to reduce the input force needed to move an object. This is only possible when the input force acts over a long distance and the object moves a shorter distance.

However, sometimes levers are designed to increase the input force needed to move an object. Which of the following is most likely an example of this type of lever?
A.
a catapult
B.
a see-saw
C.
a wheelbarrow
D.
a crowbar

Physics
1 answer:
Alja [10]3 years ago
4 0

Answer:

work being done on an object.

Answer. A. A man pushes a couch across the room

diagram identifies an axle:

Answer: B. Z

simple machine described as a shaft at the center of a wheel:

Answer: D. Wheel and axle

Type of lever:

A. a catapult

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A spring has a equilibrium length of 10.0 cm. When a force of 40.0 N is applied to the spring, the spring has a length of 14.0 c
mote1985 [20]

Answer:

The value of the spring constant of this spring is 1000 N/m

Explanation:

Given;

equilibrium length of the spring, L = 10.0 cm

new length of the spring, L₀ = 14 cm

applied force on the spring, F = 40 N

extension of the spring due to applied force, e = L₀ - L = 14 cm - 10 cm = 4 cm

From Hook's law

Force applied to a spring is directly proportional to the extension produced, provided the elastic limit is not exceeded.

F ∝ e

F = ke

where;

k is the spring constant

k = F / e

k = 40 / 0.04

k = 1000 N/m

Therefore, the value of the spring constant of this spring is 1000 N/m

7 0
3 years ago
Assume it takes 5.00 minutes to fill a 50.0-gal gasoline tank. (1 U.S. gal = 231 in.3).
dolphi86 [110]

               (50 gal / 5 min) x (.0037854 m³/gal) x (1 min / 60 sec)

         =    (50 · 0.0037854 · 1) / (5 · 60)          m³/sec

         =                  0.000631  m³/sec
7 0
3 years ago
What happens when the voltage increases and the resistance stays the same in a electrical circuit?
Orlov [11]

Answer:

The current in the circuit increases

Explanation:

The ohm's law states that the potential across a circuit is proportional to the current in the circuit.

                                             V ∝ I

Where 'V' is the potential difference across the circuit and 'I' is the current in the circuit.

The proportionality constant present in the equation is the resistance of the circuit. Hence, the equation becomes

                                             V = IR

According to the equation, when V is directly proportional to 'I' where 'R' remains as constant, then the change in 'V is brings change in 'I' to make the equation valid.

So, when there is an increase in the voltage, the current on the circuit increases.

4 0
2 years ago
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the dist
Sidana [21]

Complete Question

The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.08m. She sets the pendulum swinging, and her collaborators carefully count 101 complete cycles of oscillation during 2.00×102 s. What is the result? acceleration due to gravity:acceleration due to gravity: m/s2

Answer:

The acceleration due to gravity is  g = 167.2 \ m/s^2  

Explanation:

From the question we are told that

     The length of the simple pendulum is L = 1.081.08 \ m

      The number of cycles is  N =  101

       The time take is  t =  2.00 *10^{2 \ }s

Generally the period of this oscillation is mathematically evaluated as

         T = \frac{N}{t }

substituting values

         T = \frac{101}{2.0*10^2 }

        T = 0.505 \  s

The period of this oscillation is mathematically represented  as

               T = 2 \pi \sqrt{\frac{l}{g} }

making g the subject of the formula we have

              g = \frac{L}{[\frac{T}{2 \pi } ]^2 }

              g = \frac{4 \pi ^2 L }{T^2 }

Substituting values

               g = \frac{4 * 3.142 ^2  * 1.08 }{505.505^2 }

               g = \frac{4 * 3.142 ^2  * 1.08 }{0.505^2 }  

              g = 167.2 \ m/s^2  

7 0
2 years ago
Two tuning forks A and B when sounded together produce 5 beats per second. The tuning fork A has frequency 480Hz. The fork B is
BartSMP [9]
<h2>The frequency of tuning fork B is 475 Hz</h2>

Explanation:

The number of beats produced is equal to the frequency difference between the two tuning forks .

The frequency of A = 480 Hz

Thus the frequency of B can be = 485 or 475 Hz

When B is filed , its frequency increases and it start producing 2 beats with A .

Thus it frequency must be 475 Hz , by filing , it increases to 478 Hz .

By which it gives  480 - 478 = 2 beats per second .

This cannot happen with frequency 485 , because by filing this difference increases in place of decreasing .

5 0
3 years ago
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