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igomit [66]
3 years ago
7

NEED HELP ASAP PLEASEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Which of the following is an example of work being done on an object?
A.
A man pushes a couch across the room.
B.
A prism scatters ultraviolet light into visible light.
C.
A box rests on the floor.
D.
Water in a pot changes into steam.

In the diagram above, which letter identifies an axle?
A.
X
B.
Z
C.
Y
D.
W

Which simple machine can be described as a shaft that is attached to the center of a wheel?
A.
lever
B.
inclined plane
C.
pulley
D.
wheel and axle

Usually, levers are used to reduce the input force needed to move an object. This is only possible when the input force acts over a long distance and the object moves a shorter distance.

However, sometimes levers are designed to increase the input force needed to move an object. Which of the following is most likely an example of this type of lever?
A.
a catapult
B.
a see-saw
C.
a wheelbarrow
D.
a crowbar

Physics
1 answer:
Alja [10]3 years ago
4 0

Answer:

work being done on an object.

Answer. A. A man pushes a couch across the room

diagram identifies an axle:

Answer: B. Z

simple machine described as a shaft at the center of a wheel:

Answer: D. Wheel and axle

Type of lever:

A. a catapult

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What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your an
AveGali [126]

Complete Question

A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the wheel starts turning, you are at the very top.

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.

Answer:

\phi=123.75

Explanation:

From the question we are told that:

Height h=27m

Period T=32sec

Time t=75sec

Generally the equation for angular velocity is mathematically given by

\omega=\frac{2 \pi}{T}

\omega=\frac{2 \pi}{32}

\omega=0.196rad/s

Therefore

\theta=\omega t

\theta=0.196rad/s*75sec

\theta=843.75 \textdegree

Therefore

\phi=\theta-2(360)

\phi=123.75

6 0
3 years ago
At which type of boundary between two tectonic plates is an earthquake or a tsunami most likely to form?
Fofino [41]

Answer:

B. convergent boundary

Explanation:

Convergent boundaries, where ocean plates are subducted at trenches, produce the most tsunamis because they produce the largest earthquakes

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Humans sleep in cycles, usually two or three cycles per night. There is a point in each cycle when waking up will leave the slee
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niobium metal becomes a superconductor when cooled below 9 k. its superconductivity is destroyed when the surface magnetic field
Furkat [3]

Niobium wire with a 2.60 mm diameter has a maximum current capacity of 500 A while still remaining superconducting.

<h3>Describe the present.</h3>

Current is the rate at which charge passes from one point on a circuit to another. In a circuit, a significant current flows when several coulombs or charge pass over the cross section of a wire. When the charge carriers are firmly packed inside the wire, high currents can be generated at low speeds.

<h3>What do current and electron actually mean?</h3>

Electron movement is referred to as electron current. The positive terminal receives electrons that are released by the negative terminal. Traditional current, usually referred to as just current, exhibits behavior consistent with positive charge carriers being the source of current flow. Regular current is received at the positive end and then flows to a negative terminal.

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5 0
1 year ago
A stoplight with weight 100 N is suspended at the midpoint of a cable strung between two posts 200 m apart. The attach points fo
Tasya [4]

There are 3 forces acting on the stoplight:

• its weight <em>W</em>, with magnitude <em>W</em> = 100 N, pointing directly downward

• two tension forces <em>T</em>₁ and <em>T</em>₂ with equal magnitude <em>T</em>₁ = <em>T</em>₂ = <em>T</em> = 1000 N, both making an angle of <em>θ</em> with the horizontal, but one points left and the other points right

The stoplight is in equilibrium, so by Newton's second law, the net vertical force acting on it is 0, such that

∑ <em>F</em> = <em>T</em>₁ sin(<em>θ</em>) + <em>T</em>₂ sin(180° - <em>θ</em>) - <em>W</em> = 0

We have sin(180° - <em>θ</em>) = sin(<em>θ</em>) for all <em>θ</em>, so the above reduces to

2<em>T</em> sin(<em>θ</em>) = <em>W</em>

2 (1000 N) sin(<em>θ</em>) = 100 N

sin(<em>θ</em>) = 0.05

<em>θ</em> ≈ 2.87°

If <em>y</em> is the vertical distance between the stoplight and the ground, then

tan(<em>θ</em>) = (15 m - <em>y</em>) / (100 m)

Solve for <em>y</em> :

tan(2.87°) = (15 m - <em>y</em>) / (100 m)

<em>y</em> = 15 m - (100 m) tan(2.87°)

<em>y</em> ≈ 9.99 m

3 0
3 years ago
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