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igomit [66]
3 years ago
7

NEED HELP ASAP PLEASEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Which of the following is an example of work being done on an object?
A.
A man pushes a couch across the room.
B.
A prism scatters ultraviolet light into visible light.
C.
A box rests on the floor.
D.
Water in a pot changes into steam.

In the diagram above, which letter identifies an axle?
A.
X
B.
Z
C.
Y
D.
W

Which simple machine can be described as a shaft that is attached to the center of a wheel?
A.
lever
B.
inclined plane
C.
pulley
D.
wheel and axle

Usually, levers are used to reduce the input force needed to move an object. This is only possible when the input force acts over a long distance and the object moves a shorter distance.

However, sometimes levers are designed to increase the input force needed to move an object. Which of the following is most likely an example of this type of lever?
A.
a catapult
B.
a see-saw
C.
a wheelbarrow
D.
a crowbar

Physics
1 answer:
Alja [10]3 years ago
4 0

Answer:

work being done on an object.

Answer. A. A man pushes a couch across the room

diagram identifies an axle:

Answer: B. Z

simple machine described as a shaft at the center of a wheel:

Answer: D. Wheel and axle

Type of lever:

A. a catapult

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A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
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Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

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Distance from the center of platform = 1.07 m

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Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = \frac{MR^2}{2}

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia (I_y_y )  of the system with respect to the axis yy.

⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

⇒ I_y_y=289.088\ kg.m^2

The moment of inertia of the system is 289.088 kg.m^2

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