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Tasya [4]
4 years ago
13

A 20.0 mL sample of glycerol has a mass of 25.2 grams. What is the mass of a 57 mL sample of glycerol?

Chemistry
2 answers:
DerKrebs [107]4 years ago
5 0

Answer:

71.8 g

Explanation:

With the first sentence we can calculate the density of the sample of glycerol:

Density=\frac{mass}{volume}

Density=\frac{25.2g}{57mL}\\Density=1.26g/mL

<u>Using the density of the sample we calculate the mass of a given volume:</u>

Volume*Density=Mass

57 mL * 1.26 g/mL = 71.8 g

A 57 mL sample of glycerol weighs 71.8 g.

dsp734 years ago
4 0

Answer:

Density = 25.2 g/20.0 ml = 1.26 g/ml

57 ml x 1.26 g/ml = 71.8 g

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If you start with 227.8 grams of iron and 128 grams of oxygen to produce iron oxide, what is the limiting reagent?
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The balanced chemical equation between iron and oxygen to produce iron (III) oxide is,

4Fe(s) + 3O_{2}(g) ---> 2Fe_{2}O_{3}(s)

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Mass of iron (III) oxide produced from oxygen=4 mol O_{2}*\frac{2 molFe_{2}O_{3}}{3 mol O_{2}}*\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} =  425.84 g Fe_{2}O_{3}

Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.

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