Answer:
Manganese trinitrate or manganese(III) nitrate
Explanation:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
Explanation:
Reacting bromide (Br₂) with sodium iodine (NaI) will produce sodium bromide (NaBr) and iodine (I₂).
To balance the equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
where:
l - liquid
s - solid
This is a single replacement reaction because an element in a compound is replaced by another element. Generally a single replacement reaction is represented as: A + BC → AC + B
Learn more about:
types of chemical reactions
brainly.com/question/10105284
balancing chemical equations
brainly.com/question/13908054
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Answer:
Es la tercera por qué cuando el material varía va cambiando de estado
Explanation:
<span><span>When you write down the electronic configuration of bromine and sodium, you get this
Na:
Br: </span></span>
<span><span />So here we the know the valence electrons for each;</span>
<span><span>Na: (2e)
Br: (7e, you don't count for the d orbitals)
Then, once you know this, you can deduce how many bonds each can do and you discover that bromine can do one bond since he has one electron missing in his p orbital, but that weirdly, since the s orbital of sodium is full and thus, should not make any bond.
However, it is possible for sodium to come in an excited state in wich he will have sent one of its electrons on an higher shell to have this valence configuration:</span></span>
<span><span /></span><span><span>
</span>where here now it has two lonely valence electrons, one on the s and the other on the p, so that it can do a total of two bonds.</span><span>That's why bromine and sodium can form </span>
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