Answer:
u 2
and stay positive :)
Step-by-step explanation:
Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
I think it’s 34 hope this helps
Answer:
Simplified answer = 11.1 - 10y = 0
y = 1.11
Step-by-step explanation:
6 - 2y + (-8y) + 5.1 = 0
6 + 5.1 -2y -8y = 0
Add like terms
11.1 - 10y = 0
(This is simplified, but if you want to solve for y, continue)
11.1 - 10y = 0
÷10 ÷10
1.11 - y = 0
y = 1.11 because 1.11 - 1.11 is 0
I Hope That This Helps!
Answer:
This will help you answer the question
The most important thing to remember when writing a proportion is to keep the units the same in both ratios. You know the fractions are equivalent because each shows the ratio of girls to boys in the class. The first fraction shows the known ratio of girls to boys.