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3 years ago

I’m confused on this one

Mathematics

1 answer:

Blababa [14]3 years ago

3 0

The three medians of a triangle intersect at the centroid of the triangle.
The centroid is 2/3 of the way from a vertex to the midpont of the opposite side.

BG = (2/3)BF

BG = (2/3) * 9

BG = 6

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Do 18/14 and 10/15 have the same vaule explain why

jek_recluse [69]

Answer:

Step-by-step explanation:

18/14 and 10/15 don't have the same value. Only equivalent fractions have same value.

These two are not equivalent fractions

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3 years ago

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A woman salary of $42 , 000 per week is increased by 10%. what is her new salary?

erica [24]

4200

42,000/10=4200

Hope it helps :)

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3 years ago

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Use the graph below to answer the question that follows:

Serhud [2]

Answer:

The trignometric function that best represents the graph is:

$f(x)=4 \sin(x-\dfrac{\pi}{2})$

Step-by-step explanation:

It is given that the trignometric function passes through:

(0,-4) , (π/2,0) , (π,4) , (3π/2,0) , (2π,-4) and (5π/2,0) and (3π,4)

We will check these points in each of the given options and see what holds true.

$f(x)=4\cos (x-\dfrac{\pi}{2})$

When we put x=0 we obtain:

$f(0)=4\cos (0-\dfrac{\pi}{2})\\\\f(0)=4\cos (-\dfrac{\pi}{2})\\\\f(0)=4\cos (\dfrac{\pi}{2})\\\\Since,\\\cos (-\theta)=\cos (\theta)\\\\Hence,\\f(0)=0\neq -4$

Hence, option 2 is incorrect.

$f(x)=4 \sin(x-\dfrac{\pi}{2})+1$

When we put x=0 we get:

$f(0)=4 \sin (0-\dfrac{\pi}{2})+1\\\\f(0)=4 \sin (-\dfrac{\pi}{2})+1\\\\f(0)=-4\sin (\dfrac{\pi}{2})+1\\\\Since,\\\sin (-\theta)=\sin (\theta)\\Hence,\\f(0)=-4+1\\\\f(0)=-3\neq -4$

Hence, option 3 is incorrect.

$f(x)=4\cos (x-\dfrac{\pi}{2})+1$

When we put x=0 we obtain:

$f(0)=4\cos (0-\dfrac{\pi}{2})+1\\\\f(0)=4\cos (-\dfrac{\pi}{2})+1\\\\f(0)=4\cos (\dfrac{\pi}{2})+1\\\\Since,\\\cos (-\theta)=\cos (\theta)\\\\Hence,\\f(0)=1\neq -4$

Hence, option 4 is incorrect.

$f(x)=4 \sin(x-\dfrac{\pi}{2})$

When we put each of the x-value we see that the y-value also holds.

Hence, option 1 is true.

Also we can see in the graph.

3 0

4 years ago

In problems 1 and 2 let f(x) = 3x +2 and g(x) = x-3

klemol [59]

In this question, we're solving the expressions.

Problem 1:

For problem 1, f(x) + g(x) means that we're combining both of the equations together by adding.

Solve:

3x + 2 + x - 3

Combine like terms:

4x + 2 - 3

Answer to problem 1: 4x - 1

Problem 2:

In this problem, you're getting both of the expressions and combining them; however, you would need to plug in -1 to the x variable in both of the expressions.

Your problem should look like this:

3(-1) + 2 - 1 - 3

Solve:

3(-1) + 2 - 1 - 3

-3 + 2 - 1 - 3

-1 - 1 - 3

-2 - 3

-5

Answer to problem 2: -5

5 0

3 years ago

MATH To provide additional employment and add

aniked [119]

130,423.89 is your answer

6 0

3 years ago