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solong [7]
3 years ago
11

In a school, the probability that a student takes environmental science and geography is 0.72.The probability that a student tak

es technology is 0.25. What is probability that a student takes geography given that the student is taking environmental science?
Mathematics
1 answer:
blondinia [14]3 years ago
6 0
I believe it would be 0.75

If not that the only other thing I could think of would be 0.03, but it says he is already taking environmental science.
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If there are 30 boys and 50 girls in a room, fill out all of the possible ratios of boys to girls that could be made. They alrea
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3 years ago
Solve the equation 425x=850
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Answer:

x=2

Step-by-step explanation:

To solve this, you must isolate x. To do this, divide both sides by 425 because that is what x is being multiplied by (and dividing is its opposite). Then, you get the answer, x=2.

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What are the solutions to the equation (x+5)2=32 ?
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x = 11

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8 0
2 years ago
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Given the following sets:
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<h3>Answer:  10</h3>

===========================================================

Explanation:

Even though your teacher doesn't want you to list the items of the set, it helps to do so.

We'll be working with these two sets

A = {b, d, f, h, j, I, n, p, r, t}

C =  {d, h, I, p, t}

When we union them together, we combine the two sets together. Think of it like throwing all the letters in one bin rather than two bins.

A u C = {b, d, f, h, j, I, n, p, r, t,   d, h, I, p, t  }

The stuff that isn't bolded is set A, while the stuff that is bolded is set C

After we toss out the duplicates, we end up with this

A u C = {b, d, f, h, j, I, n, p, r, t}

But wait, that's just set A. Notice how everything in set C can be found in set A. This indicates set C is a subset of set A.

That's why all of the stuff in bold was tossed out (because they were duplicates of stuff already mentioned).

Once we determine what set A u C looks like, we count out the number of items in that set to determine the final answer.

There are 10 items in {b, d, f, h, j, I, n, p, r, t} which means 10 is the final answer.

----------------------------

An alternative method is to use the formula below

n(A u C) = n(A) + n(C) - n(A and C)

n(A u C) = 10 + 5 - 5

n(A u C) = 10

The notation n(A and C) counts how many items are found in both sets A and C at the same time. But as mentioned earlier, this is identical to just counting how many items are in set C. So we'll have n(C) cancel out with itself.

In short, n(A u C) = n(A) = 10

8 0
3 years ago
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