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frosja888 [35]
3 years ago
11

In 2016, London elected its first ________ mayor.

Mathematics
1 answer:
lapo4ka [179]3 years ago
6 0
B. Muslim
Sadiq Kahn identifies as a Muslim. 
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A Triangular Park ABC has sides 120 m, 80m and 50m. a gardener has to put a fence all around it and also plant grass inside. How
Vadim26 [7]

The perimeter = sum of all sides

= 120 + 80 + 50

= 250

So 250 - 3

247

Left space for gate

Now cost of fencing = Rs 20/per meter

= 247 × 20

= Rs 4,940

Now the area of the triangular park can be found using heron's formula

S = (a+b+c)/2

S = (120+80+50)/2

S = 250/2

S = 125

Now

Herons formula = √s(s-a)(s-b)(s-c)

√125(125-120)(125-80)(120-50)

√125(5)(45)(70)

√5×5×5×5×5×3×3×5×14

After Making pairs

5×5×5×3√14

375√14

Therefore 375√14m is the area of the triangular park

Must click thanks and mark brainliest

7 0
3 years ago
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Aiden borrows a book from a public library. He read a few pages on day one. On day two, he reads twice the number of pages than
Thepotemich [5.8K]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Find the value of x and y
slava [35]

Answer:

Step-by-step explanation:

OS ≅ OU, so we will set those 2 expressions equal to each other and solve for y:

6y = 42 so

y = 7

Same goes for OT and OV:

x + 5 = 23 so

x = 18 and

SU = 84

5 0
3 years ago
A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin
Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean \mu=50

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

P(X\leq 55)=1-P(X>55)

P(X\leq 55)=1-0.14

P(X\leq 55)=0.86

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

Where, \sigma is standard deviation

Substitute the values,

z=\frac{x-\mu}{\sigma}

1.08=\frac{55-50}{\sigma}

1.08=\frac{5}{\sigma}

\sigma=\frac{5}{1.08}

\sigma=4.62

The standard deviation of weight for this species of cockroaches is 4.62.

4 0
3 years ago
Describe the geometric effect of the transformation LA????????
fomenos

Answer:

Step-by-step explanation:

Hhhy

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