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3 years ago

I will a!or u BRAINLIEST pls answer this question!!!

Mathematics

2 answers:

Alex_Xolod [135]3 years ago

8 0

I think it’s B I’m not surr

Veseljchak [2.6K]3 years ago

6 0

It’s c lol hope this helps

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The area of a rectangle is 64 square centimeters. The rectangle is 4 centimeters wide. How long is the rectangle.

VLD [36.1K]

The Area is the width<span> times the </span>height<span>: A = w x h;
Then, 64 = w x h;
h = 4 + w;
64 = 4w + w^2;
w^2 + 4w - 64 = 0;
We solve this equation: w1 </span>≈ 6,24 > 0 (okay); w2 ≈ - 10,24 < 0 (not okay);
<span>Finally, h1 </span>≈ 10,24;<span>

</span>

4 0

3 years ago

You do not need to flip the inequality sign when solving the inequality -3t + 7 ≥ 9. True False

nordsb [41]

Hello!

It is False because t is multiplied by a negative number, so to solve for it you will need to divide both sides by -3 which mean you have to flip the sign.

Hope this helps!

7 0

3 years ago

Solve the equation. <br><br><br> 12=2+z/-6

Bogdan [553]

Answer:

$\boxed{\bold{z=-60}}$

Step-by-step explanation:

Switch Sides

$\bold{2+\frac{z}{-6}=12}$

Subtract 2 From Both Sides

$\bold{2+\frac{z}{-6}-2=12-2}$

Simplify

$\bold{\frac{z}{-6}=10}$

Multiply Both Sides By -6

$\bold{\frac{z\left(-6\right)}{-6}=10\left(-6\right)}$

Simplify

$\bold{z=-60}$

3 0

3 years ago

Read 2 more answers

Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$

3 0

3 years ago

The length of a rectangle is 6 feet more than three times the width of the

Nesterboy [21]

Answer:

<h2>width = 6 feet</h2>

Step-by-step explanation:

let l be the length of the rectangle

let w be the width of the rectangle

The statement

The length of a rectangle is 6 feet more than three times the width of the

rectangle is written as

l = 6 + 3w

From the question

l = 24 feet

Substitute the value into the above formula and solve for the width

That's

24 = 6 + 3w

3w = 24 - 6

3w = 18

Divide both sides by 3

w = 6

Therefore

<h3>width = 6 feet</h3>

Hope this helps you

3 0

3 years ago