Answer:
614 034 kg
Explanation:
n = m/Mm
m = n * Mm
Mm(MgSO4) = 1 * 24.3 * 1 * 32.1 * 4 * 16 = 49921.92
m = 12.3 * 49921.92
m = 614 034 kg
Answer:
When one object uses force to move the other.
Explanation:
This is called Thrust.Thrust is used in airplane engines,or an engine can be a source of Thrust,we use our legs to Thrust us forward when we walk!
The balanced chemical equation for the above reaction is as follows ;
Mg + 2HCl —> MgCl2 + H2
The stoichiometry of Mg to HCl is 1:2
This means that 1 mol of Mg reacts with 2 mol of HCl
Equal amounts of both Mg and HCl have been added. One reagent is the limiting reactant and other reactant is in excess.
Limiting reactant is the reagent that is fully used up in the reaction and the amount of Product formed depends on the amount of limiting reactant present.
In this reaction if Mg is the limiting reactant, 4.40 moles of Mg should react with 4.40x2 -8.80 moles of HCl.
But only 4.40 moles of HCl present therefore HCl is the limiting reactant that reacts with 4.40/2 = 2.20 moles of Mg
Stoichiometry of HCl to MgCl2 is 2:1
Since HCl moles reacted -4.40 mol
Then MgCl2 moles formed are 4.40/2 = 2.20 mol of MgCl2
Answer:
Explanation:
Carbon Dioxide-CO2
To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number.
Molar mass of CO2=
C:12.0g+O:16.0gx2=44.0g CO2
25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2
= 3.42x10 23 molecules CO2
1 | 44.0g CO2 | 1 mol CO2
Now to get the number of oxygen atoms.
Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23)
So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000
