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3 years ago

What is produced when calcium reacts with fluorine in a synthesis reaction

2 answers:

5 0

<span>Calcium fluoride is produced. It is one Calcium atom bonded to two fluoride atoms. The Calcium atom receives one electron from one fluoride and a second electron from the second fluoride atom. As a result of receiving the two electrons, Calcium will have a negative charge. The two fluorides become positive from losing an electron. The positive and negative charge attraction keeps the atoms close together to form an ionic bond.</span>

suter [353]3 years ago

4 0

Calcium floride .....

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A student pushes a 5 kg box initially at rest along a flat, rough table with a rightward force of 10 N. The frictional force act

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Answer:

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3 years ago

How many atoms make up this compound? NaOH A. 1 B. 2 C. 3 D. 4

777dan777 [17]

Just learned this in chemistry. There are no subscripts, therefor each element only has 1 atom. Na has 1, O has 1 and H has one. There are 3 atoms.

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3 years ago

Moving company uses a machine to raise a 900 Newton refrigerator to the second floor of a building machine consists of a single

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3 years ago

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The force between charged objects decreases when their separation ..... A)increase<br> B)decrease

weqwewe [10]

Answer A: When their separation increases.

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3 years ago

Imagine that asteroid A that has an escape velocity of 50 m/s. If asteroid B has twice the mass and twice the radius, it would h

padilas [110]

Answer:

The same as the escape velocity of asteorid A (50m/s)

Explanation:

The escape velocity is described as follows:

$v=\sqrt{\frac{2GM}{R}}$

where $G$ is the universal gravitational constant, $M$ is the mass of the asteroid and $R$ is the radius

and since the scape velocity is 50m/s:

$50m/s=\sqrt{\frac{2GM}{R}}$

Now, if the astroid B has twice mass and twice the radius, we have that tha mass is: $2M$

and the radius is: $2R$

inserting these values into the formula for escape velocity:

$v=\sqrt{\frac{2G(2M)}{2R} } =\sqrt{\frac{4GM}{2R} } =\sqrt{\frac{2GM}{R} }$

and we have found that $50m/s=\sqrt{\frac{2GM}{R}}$ , so the two asteroids have the same escape velocity.

We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.

The answer is

Asteroid B would have an escape velocity the same as the escape velocity of asteroid A

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3 years ago