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arsen [322]
3 years ago
10

What is produced when calcium reacts with fluorine in a synthesis reaction

Physics
2 answers:
OLga [1]3 years ago
5 0
<span>Calcium fluoride is produced. It is one Calcium atom bonded to two fluoride atoms. The Calcium atom receives one electron from one fluoride and a second electron from the second fluoride atom. As a result of receiving the two electrons, Calcium will have a negative charge. The two fluorides become positive from losing an electron. The positive and negative charge attraction keeps the atoms close together to form an ionic bond.</span>
suter [353]3 years ago
4 0
Calcium floride .....
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A toddler pushes his 7.0 kg toy box at a relatively constant velocity across the tiled floor of the family room applying a horiz
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Answer:The coefficient of friction between the box and the floor,  = 1.456 × 10⁻²

Explanation:

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3 years ago
Robert Hook discovered cells when viewing a _____ under a microscope.
sp2606 [1]
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3 0
3 years ago
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Convection currents in the Earth's mantle cause plate movement which can cause all except
Dominik [7]
The answer is B. hurricanes 
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3 years ago
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A hollow cylinder with an inner radius of 5 mm and an outer radius of 26 mm conducts a 4-A current flowing parallel to the axis
bearhunter [10]

Answer:

B = 38.2μT

Explanation:

By the Ampere's law you have that the magnetic field generated by a current, in a wire, is given by:

B=\frac{\mu_o I_r}{2\pi r}     (1)

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

r: distance from the center of the cylinder, in which B is calculated

Ir: current for the distance r

In this case, you first calculate the current Ir, by using the following relation:

I_r=JA_r

J: current density

Ar: cross sectional area for r in the hollow cylinder

Ar is given by  A_r=\pi(r^2-R_1^2)

The current density is given by the total area and the total current:

J=\frac{I_T}{A_T}=\frac{I_T}{\pi(R_2^2-R_1^2)}

R2: outer radius = 26mm = 26*10^-3 m

R1: inner radius = 5 mm = 5*10^-3 m

IT: total current  = 4 A

Then, the current in the wire for a distance r is:

I_r=JA_r=\frac{I_T}{\pi(R_2^2-R_1^2)}\pi(r^2-R_1^2)\\\\I_r=I_T\frac{r^2-R_1^2}{R_2^2-R_1^2}  (2)

You replace the last result of equation (2) into the equation (1):

B=\frac{\mu_oI_T}{2\pi r}(\frac{r^2-R_1^2}{R_2^2-R_1^2})

Finally. you replace the values of all parameters:

B=\frac{(4\pi*10^{-7}T/A)(4A)}{2\PI (12*10^{-3}m)}(\frac{(12*10^{-3})^2-(5*10^{-3}m)^2}{(26*10^{-3}m)^2-(5*10^{-3}m)^2})\\\\B=3.82*10^{-5}T=38.2\mu T

hence, the magnitude of the magnetic field at a point 12 mm from the center of the hollow cylinder, is 38.2μT

8 0
3 years ago
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 81 N acts on
tensa zangetsu [6.8K]

Answer:

18 N

Explanation:

You have to do:

81 N: 9 ms2= x: 2 ms2

6 0
3 years ago
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