Answer:
35870474.30504 m
Explanation:
r = Distance from the surface
T = Time period = 24 h
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
m = Mass of the Earth = 5.98 × 10²⁴ kg
Radius of Earth = 
The gravitational force will balance the centripetal force
From Kepler's law we have relation
Distance from the center of the Earth would be
Answer: Option (C) is the correct answer.
Explanation:
As we know that metals are able to conduct electricity so, when a negatively charges rod is kept closer to the left sphere then electrons will enter the sphere.
Since, like charges repel each other. Hence, some of the negative changes from the rod will repel the negative charges of left sphere.
As both left and right spheres are touching each other so, the electrons will move towards the right sphere. As a result, there will be too many electrons (negative charge) present on the right sphere and very less electrons present in the left sphere.
Thus, we can conclude that the statement right sphere is negatively charged, another is charged positively, is true.
Equations of motion (EoM) use EoM <span>v2=u2+2ax</span> to establish velocities at positions shown in blue in drawing from EoM v=u+at for final 1 second of flight time, we can say v=u+g(1) <span><span>2gH−−−−√</span>=<span><span>2g1625H</span>−−−−−−√</span>+g</span><span> then, solve for H [in terms of g]
</span>
Answer: 7840N
Explanation:
Given that
Potential energy = ?
Mass of sled = 20-kg
Distance = 40 meters
Acceleration due to gravity = 9.8m/s^2
Recall that potential energy is the energy possessed by a body at rest
i.e potential energy = mass m x acceleration due to gravity g x distance h
P.E = mgh
P.E = 20kg x 9.8m/s^2 x 40m
P.E = 7840N
Thus, the potential energy of the sled is 7840N
Explanation:
The given data is as follows.
= 57 kg, 
= 79 kg
= 6.5 m, 
= (6.5 - 1.9) m = 4.6 m
(a) The sum of torque ends about far end is as follows.
= 0
= 0
T = 828 N
Therefore, 828 N is the tension in the cable closer to the painter.
(b) Now, we will calculate the sum about close ends as follows.
= 0
T= 506 N
Therefore, 506 N is the tension in the cable further from the painter.
