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Pavel [41]
3 years ago
6

Cocking your head would be most useful for detecting the ______ of a sound.

Physics
2 answers:
kykrilka [37]3 years ago
8 0

Answer:

It would be most useful for detecting WHERE a sound may come from or the location of said sound.

Explanation:

statuscvo [17]3 years ago
5 0
Cocking your head would be most useful for detecting the LOCATION of a sound.
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A crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.58 m/s. The pulling force is 110 N parallel to th
kari74 [83]

Given that,

Mass = 9.2 kg

Force = 110 N

Angle = 20.2°

Distance = 5.10 m

Speed = 1.58 m/s

(A). We need to calculate the work done by the gravitational force

Using formula of work done

W_{g}=mgd\sin\theta

Where, w = work

m = mass

g = acceleration due to gravity

d = distance

Put the value into the formula

W_{g}=9.2\times(-9.8)\times5.10\sin20.2

W_{g}=-158.8\ J

(B). We need to calculate the increase in internal energy of the crate-incline system owing to friction

Using formula of potential energy

\Delta U=-W

Put the value into the formula

\Delta U=-(-158.8)\ J

\Delta U=158.8\ J

(C). We need to calculate the work done by 100 N force on the crate

Using formula of work done

W=F\times d

Put the value into the formula

W=100\times5.10

W=510\ J

We need to calculate the work done by frictional force

Using formula of work done

W=-f\times d

W=-\mu mg\cos\theta\times d

Put the value into the formula

W=-0.4\times9.2\times9.8\cos20.2\times5.10

W=-172.5\ J

We need to calculate the change in kinetic energy of the crate

Using formula for change in kinetic energy

\Delta k=W_{g}+W_{f}+W_{F}

Put the value into the formula

\Delta k=-158.8-172.5+510

\Delta k=178.7\ J

(E). We need to calculate the speed of the crate after being pulled 5.00m

Using formula of change in kinetic energy

\Delta k=\dfrac{1}{2}m(v_{2}^2-v_{1}^{2})

v_{2}^2=\dfrac{2\times\Delta k}{m}+v_{1}^2

Put the value into the formula

v_{2}^2=\dfrac{2\times178.7}{9.2}+1.58

v_{2}=\sqrt{\dfrac{2\times178.7}{9.2}+1.58}

v_{2}=6.35\ m/s

Hence, (A). The work done by the gravitational force is -158.8 J.

(B). The increase in internal energy of the crate-incline system owing to friction is 158.8 J.

(C). The work done by 100 N force on the crate is 510 J.

(D). The change in kinetic energy of the crate is 178.7 J.

(E). The speed of the crate after being pulled 5.00m is 6.35 m/s

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3 years ago
What does it mean to say that science is a “systematic” process?
Maurinko [17]
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Answer:

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