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Degger [83]
3 years ago
5

A small metal bar whose temperature is 30 C is dropped into a container of 75 C

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0

It would take about 40 seconds for the temperature to reach 70°C and 44 second to reach 74°C.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

Let y represent the temperature of the metal bar after x seconds, hence:

Since the metal bar has an initial temperature of 30°C, hence:

b = 30, also m = 1°C (increase), The equation becomes:

y = 1(x) + 30 = x + 30

To reach 70°C:

70 = x + 30

x = 40 seconds

To reach 74°C:

74 = x + 30

x = 44 seconds

It would take about 40 seconds for the temperature to reach 70°C and 44 second to reach 74°C.

Find out more on Linear equation at: brainly.com/question/14323743

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2 years ago
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Answer:

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Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3
Basile [38]

Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

\displaystyle \rho=\frac{m}{V}

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

m=\rho.V

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

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\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3

Calculating:

V=523.6\ cm^3

The mass is:

m=8.09 gr/cm^3 \cdot 523.6\ cm^3

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