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2 years ago

7

Using insulate gloves, Ms. Sanders transferred a few pieces of dry ice to a flask and covered it with a balloon. After a few min

utes the students observed the balloon starting to inflate. Explain what was happening in the flask and balloon to cause it to inflate. Pick the statement that DOES NOT apply to the changes.
A) The dry ice changed from a solid to a gas at room temperature.
B) The carbon dioxide gas had more kinetic energy than the solid carbon dioxide.
C) Rapidly moving carbon dioxide gas molecules moved into the balloon and inflated it.
D) As the temperer increased, the solid carbon dioxide changed phase: solid - liquid - gas.

2 answers:

Cloud [144]2 years ago

7 0

D) As the tempered increased, the solid carbon dioxide changed phase: solid- liquid- gas

gavmur [86]2 years ago

5 0

Answer:

i think the answer is D

Explanation:

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2C8H18 (1) + 2502 (g) --> 16CO2 (g) + 18H2O (g)

Makovka662 [10]

Answer:

One gallon of octane produces approximately 7000 L of carbon dioxide.

Note:

I believe that the mass of octane should have been given as 2661 g. However, I understand that your instructor probably gave you this problem, so I will use 4000 g for the approximate mass of one gallon of octane. You can rework the problem on your own, substituting the correct masses of octane if you wish.

Step1. You must first determine the number of moles that are in 4000 g of octane, using the molar mass of octane. Step 2. Then you must determine the number of moles of carbon dioxide that can be produced by that number of moles of octane, based on the mole ratio between octane and carbon dioxide in the balanced equation. Step 3. Then use the ideal gas law to determine the volume in liters of carbon dioxide that can be formed.

5 0

1 year ago

9. Write a balanced nuclear equation for the following: The isotope Strontium-90 decays by Q-

Sergio039 [100]

Answer: $_{38}^{90}\textrm{Sr}\rightarrow _{36}^{86}\textrm{Kr}+_2^4\textrm{He}$

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

General representation of an element is given as: $_Z^A\textrm{X}$

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

General representation of alpha decay :

$_Z^A\textrm{Sr}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha$

The balanced nuclear equation when the isotope Strontium-90 decays by Q- decay is :

$_{38}^{90}\textrm{Sr}\rightarrow _{36}^{86}\textrm{Kr}+_2^4\textrm{He}$

4 0

3 years ago

Fill in the blank. A ___ is a substance that cannot be separated into simpler substances by physical or mechanical methods such

Ganezh [65]

An element cannot be broken down any further. Elements can be found on the periodic table

8 0

2 years ago

Read 2 more answers

Calcium hydroxide is a strong base but is not very soluble ( Ksp = 5.02 X 10-6 ). What is the pH of a saturated solution of Ca(O

Misha Larkins [42]

Answer : The pH of a saturated solution is, 12.33

Explanation : Given,

$K_{sp}$ = $5.02\times 10^{-6}$

First we have to calculate the solubility of $OH^-$ ion.

The balanced equilibrium reaction will be:

$Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-$

Let the solubility will be, 's'.

The concentration of $Ca^{2+}$ ion = s

The concentration of $OH^-$ ion = 2s

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ca^{2+}][OH^-]^2$

Let the solubility will be, 's'

$K_{sp}=(s)\times (2s)^2$

$K_{sp}=(4s)^3$

Now put the value of $K_[sp}$ in this expression, we get the solubility.

$5.02\times 10^{-6}=(4s)^3$

$s=1.079\times 10^{-2}M$

The concentration of $Ca^{2+}$ ion = s = $1.079\times 10^{-2}M$

The concentration of $OH^-$ ion = 2s = $2\times (1.079\times 10^{-2}M)=2.158\times 10^{-2}M$

First we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (2.158\times 10^{-2})$

$pOH=1.67$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-1.67=12.33$

Therefore, the pH of a saturated solution is, 12.33

7 0

2 years ago

When the [H+] in a solution is 1.7 × 10−9 M, what is the pOH ? 8.80 5.23 14 8.60

kumpel [21]

PH = -log[H+]
pH = -log[1,7×10^-9]
pH = 8,77

pH + pOH = 14
pOH = 14 - 8,77
pOH = 5,23

5 0

2 years ago

Read 2 more answers