Answer:
a) The table of values represents the ordered pairs formed by the elements of the sequence (
) (range) and their respective indexes (
) (domain):

1 6
2 11
3 16
4 21
5 26
b) The algebraic expression for the general term of the sequence is
.
c) The 25th term in the sequence is 126.
Step-by-step explanation:
a) Make a table of values for the sequence 6, 11, 16, 21, 26, ...
The table of values represents the ordered pairs formed by the elements of the sequence (
) (range) and their respective indexes (
) (domain):

1 6
2 11
3 16
4 21
5 26
b) Based on the table of values, we notice a constant difference between two consecutive elements of the sequence, a characteristic of arithmetic series, whose form is:
(1)
Where:
- First element of the sequence.
- Arithmetic difference.
- Index.
If we know that
and
, then the algebraic expression for the general term of the sequence is:

c) If we know that
and
, then the 25th term in the sequence is:


The 25th term in the sequence is 126.
We have to find the mass of the gold bar.
We have gold bar in the shape of a rectangular prism.
The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.
First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:
Volume of the gold bar 
Plugging the values in the equation we get,
Volume of the gold bar 
Now that we have the volume we can find the mass by using the formula,

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:
grams
So, the mass of the gold bar is 14252.769 grams
-5x 2/7 =
−10x/7
srry if it is wrong man but that is what i got
The equation that matches the given table is
y = 10x + 40
Solution:
General equation of a line : y = mx + c
Let us find the equation of the table.
<u>Common differences of X: </u>
0 – 1 = 1, 1 – 2 = 1, 3 – 2 = 1, 4 – 3 = 1, 5 – 4 = 1
<u>Common differences of Y: </u>
50 – 40 = 10, 60 – 50 = 10, 70 – 60 = 10, 80 – 70 = 10, 90 – 80 = 10


m = 10
Substitute m = 10 in general equation of a line
y = 10x + c
To find the constant term, substitute x = 0 and y = 40.
40 = 10(0) + c
40 = 0 + c
40 = c
c = 40
Therefore the equation of a line is y = 10x + 40.
Hence the equation that matches the given table is y = 10x + 40.