Solve for x: x + = 2x

PLSSS ANSWER, 35 pointss

xxTIMURxx [149]

Answer:

1.

$(y - 5)(x + y)$

2.

${(x - y)}(x - y + a)$

3.

$(b - 3)(5b - 17)$

Step-by-step explanation:

1. The given polynomial is

$x(y - 5) - y(5 - y)$

We need to factor the second part to get:

$x(y - 5) + y(y - 5)$

We factor y-5 to obtain:

$(y - 5)(x + y)$

2. We have

${(x - y)}^{2} - a(y - x)$

We again factor -1 from the second part to get:

${(x - y)}^{2} + a(x- y)$

We now factor x-y to get:

${(x - y)}^{2} + a(x- y)$

${(x - y)}(x - y + a)$

3. We have

$2(3 - b) + 5 {(b - 3})^{2}$

We factor negative 1 from the first part to get

$- 2(b - 3) + 5 {(b - 3})^{2}$

We now factor b-3 to get:

$(b - 3)( - 2 + 5(b - 3))$

We now simplify to get:

$(b - 3)( - 2 + 5b - 15) = (b - 3)(5b - 17)$

4 0

2 years ago

The angle Johnny holds his pen on paper creates a linear pair. The measure of one angle is 13x + 7. The

tresset_1 [31]

<h3>The value of x is 4.10</h3>

<em><u>Solution:</u></em>

Given that,

The angle Johnny holds his pen on paper creates a linear pair

Angles in a linear pair are supplementary angles

Two angles are supplementary, when they add up to 180 degrees

The measure of one angle is 13x + 7

The measure of the second angle is one less than twice the first angle

Therefore,

Measure of second angle = twice the first angle - 1

Measure of second angle = 2(13x + 7) - 1

Measure of second angle = 26x + 14 - 1

Measure of second angle = 26x + 13

Therefore,

Measure of first angle + measure of second angle = 180

13x + 7 + 26x + 13 = 180

39x + 20 = 180

39x = 180 - 20

39x = 160

x = 4.1

Thus value of x is 4.10

3 0

3 years ago

HELP ASAP!!! explanation requiredd!

Mkey [24]

(7x-5)+(3x-15)=180°

10x-20=180

10x=200

x=20

(3x-15) + E = 180

3(20)-15 + E = 180

45 + E = 180

E = 135°

FG = EH = 2(y+1)

6 0

2 years ago

Read 2 more answers

Use the given pair of functions to find and simplify expressions for the following functions and state the domain of each using

Tamiku [17]

Answer:

Given functions,

$f(x) = 3 - x^2$

$g(x) = \sqrt{x}+1$

Since, by the compositions of functions,

1. (g◦f)(x) = g(f(x))

$=g(3-x^2)$

$=\sqrt{3-x^2}+1$

Since, (g◦f) is defined,

If 3 - x² ≥ 0

⇒ 3 ≥ x²

⇒ -√3 ≤ x ≤ √3

Thus, Domain = [-√3, √3]

2. (f◦g)(x) = f(g(x))

$=f(\sqrt{x}+1)$

$=3-(\sqrt{x}+1)^2$

Since, (g◦f) is defined,

If x ≥ 0

Thus, Domain = [0, ∞)

3. (f◦f)(x) = f(f(x))

$=f(3-x^2)$

$=3-(3-x^2)^2$

$=3-9-x^4+6x^2$

$=-6+6x^2-x^4$

Since, (f◦f) is a polynomial,

We know that,

A polynomial is defined for all real value of x,

Thus, Domain = (-∞, ∞)

8 0

2 years ago

PLEASE HELP ME WITH THIS!!!!!!!!

vlabodo [156]

Answer:

(9.5, 0) is in quadrant I. (-4, 7) is in quadrant II. (-1, -8) is in quadrant III.

Step-by-step explanation:

The negative signs say everything (quite literally). If there are no negative signs, it is in quadrant I. If there is one in the x-axis (the first number in an ordered pair), it is in quadrant II. If there are 2 negative signs, it is in quadrant III, and if there is one in the y-axis (the second number in an ordered pair), it is in quadrant IV.

4 0

2 years ago